Given:
JK is tangent to a circle with center H
To find:
The length of HK.
Solution:
The image is attached below.
JK = 8 mi, HJ = 15 mi
JK is tangent to a circle.
The tangent is always perpendicular to the radius.
Therefore, m∠J = 90°
Using Pythagoras theorem:
HK² = JK² + HJ²
HK² = 8² + 15²
HK² = 64 + 225
HK² = 289
HK² = 17²
Taking square root on both sides.
HK = 17
The length of HK is 17 mi.
9514 1404 393
Answer:
√42 ≈ 6.48074
Step-by-step explanation:
Put the values in place of the corresponding variables and do the arithmetic.
_____
42 = 2·3·7 is not a perfect square, nor does it have any perfect square factors. Its square root is irrational.
The sale on Friday = x = 6
The sale on Saturday = x+2 = 6 + 2 =8
The sale on Sunday = x+4 = 6+4 =10
Step-by-step explanation:
Let x be the sale of Friday
Then
x+2 will be the sale of Saturday
x+4 will be the sale of Sunday
According to the given statement, that the total sales were 24
The sale on Friday = x = 6
The sale on Saturday = x+2 = 6 + 2 =8
The sale on Sunday = x+4 = 6+4 =10
Keywords: Linear equations
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