(1) [6pts] Let R be the relation {(0, 1), (1, 1), (1, 2), (2, 0), (2, 2), (3, 0)} defined on the set {0, 1, 2, 3}. Find the foll
goldenfox [79]
Answer:
Following are the solution to the given points:
Step-by-step explanation:
In point 1:
The Reflexive closure:
Relationship R reflexive closure becomes achieved with both the addition(a,a) to R Therefore, (a,a) is 
Thus, the reflexive closure: 
In point 2:
The Symmetric closure:
R relation symmetrically closes by adding(b,a) to R for each (a,b) of R Therefore, here (b,a) is:

Thus, the Symmetrical closure:

-x+y-3z+4w=6^"dfv
+xd-y+23z=0
so x=1 and y=3
Answer:
19
Step-by-step explanation:
just use calculator. I don't really know
Answer:
x=3
Step-by-step explanation:
I did a 2-column proof for the explanation :)