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ad-work [718]
3 years ago
10

F(x) = x^2 - 12x + 50

Mathematics
2 answers:
Ierofanga [76]3 years ago
6 0

Answer:

Solve for x by completing the square:

x^2 - 12 x + 50 = 0

Subtract 50 from both sides:

x^2 - 12 x = -50

Add 36 to both sides:

x^2 - 12 x + 36 = -14

Write the left hand side as a square:

(x - 6)^2 = -14

Take the square root of both sides:

x - 6 = i sqrt(14) or x - 6 = -i sqrt(14)

Add 6 to both sides:

x = 6 + i sqrt(14) or x - 6 = -i sqrt(14)

Add 6 to both sides:

Answer: |  

| x = 6 + i sqrt(14) or x = 6 - i sqrt(14)

Step-by-step explanation:


posledela3 years ago
3 0

Answer:

x2 = 56/a = 56/16 = 7/2

Step-by-step explanation:

There are so far 8 common methods to solve quadratic equations, They are: graphing, completing the squares, quadratic formula, factoring FOIL, The Diagonal Sum Method, the Bluma Method, the popular factoring AC Method, and the new Transforming Method.

- When the quadratic equation can't be factored, the quadratic formula is the obvious choice. However, solving by formula feels like boring and repeating. In addition, school math curriculum wants students to learn, beyond the formula, a few other solving methods. That is why many quadratic equations given in problems/tests/exams are intentionally set up so that students have to solve them by other solving methods.

- When the quadratic equations can be factored, the new Transforming Method  would be the best choice. It is simple, fast, systematic, no guessing, no factoring by grouping, and no solving the 2 binomials.


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82°

Step-by-step explanation:

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<h3>Answer:  2</h3>

========================================================

Explanation:

If a number only has one factor pair, then that number must be prime. This is because prime numbers only have factors of 1 and the number itself.

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For something like the number 32, it is composite and not prime because it has the factors {1,2,4,8,16,32} and it leads to these three factor pairs: 1*32, 2*16, 4*8. This is one example showing why the answer isn't composite.

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Let's say that p is the unknown prime we want to find. The factors of this are 1 and p. We're told that "one of the factors is twice the other factor", so that must mean p = 2*1 = 2. We can see that 2 is twice that of 1.

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