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azamat
2 years ago
6

Chana and Josiah started skating at the same time in the same direction, but Josiah had a head start 10 meters past the starting

line. Chana skated 3 meters per second and Josiah skated 2 meters per second.
ANSWER:
CORRECT (SELECTED)
Josiah's distance from the starting line at a time when he is behind Chana
Point F is on line a, so it does represent Josiah's distance at a certain time. Also, point F is below line b, so it represents a distance that is less than Chana's distance.
Mathematics
1 answer:
Deffense [45]2 years ago
5 0

Point F is on line a, so it does represent Josiah's distance at a certain time. Also, point F is below line b, so it represents a distance that is less than Chana's distance. This is a distance-time graph problem.

<h3>What is the proof for the above?</h3>

Recall that Josiah had a head start of 10 meters and he skates at 2 meters per second.

Since Y is the function that represents the distance in meters from the finished line, by observation, it is clear to see that all the factors that are related to his race are adequately represented in:

y = 10 + 2x

Where 10 is the head start in meters

2 is the rate at which he skates per second; and

x is the unknown amount of time in seconds.

Given that the point F sits over 25 seconds,

that is F(y) = 10 + 2 * 25

= 60 meters.

Hence, Point F is on line a, so it does represent Josiah's distance at exactly 25 seconds.

Learn more about distance-time graphs at:
brainly.com/question/4931057
#SPJ1

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Answer:

5/16

Step-by-step explanation:

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6 0
3 years ago
Given the diagram below what is the length of segment EF
frosja888 [35]

Answer:

C is the closest.,

Step-by-step explanation:

I am assuming that the 2 trapezoids CBEF and EFDA are similar (they are similar if the 3 horizontal lines are parallel).

Corresponding sides are in the same ratio , so:

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3 years ago
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Suppose y varies inversely with X, and y = 48 when x = 3. What is the value of x when y = 24?
olganol [36]

Answer:

C. 6

Step-by-step explanation:

Recall that inverse variation is given by:

\displaystyle y=\frac{k}{x}

Where <em>k</em> is the constant of variation.

We know that <em>y</em> = 48 when <em>x</em> = 3. Substitute:

\displaystyle (48)=\frac{k}{(3)}

Solve for <em>k: </em>

<em />k=3(48)=144<em />

<em />

Hence, our equation is:

\displaystyle y=\frac{144}{x}

We want to find <em>x</em> when <em>y</em> = 24. Substitute:

\displaystyle \frac{24}{1}=\frac{144}{x}

Cross-multiply:

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Divide both sides by 24. Hence:

x=6

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3 0
3 years ago
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natta225 [31]
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7 0
3 years ago
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