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Kobotan [32]
2 years ago
9

Write equation of the log base of 3​

Mathematics
1 answer:
nikitadnepr [17]2 years ago
4 0

Answer:

see below

Step-by-step explanation:

The graph is shifted to the RIGHT so it will be a   ' x-1'

and it is shifted UP 3 units  so:

Looks like    log3 (x-1) + 3

   at x = 4 the value of the graph is 4

            log3 (4-1) + 3 = 4    CHECK !

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Can someone please give me the (Answers) to this? ... please ...<br><br> I need help….
bezimeni [28]

Answer:

see explanation

Step-by-step explanation:

2 chords intersecting inside a circle , then the product of the parts of one chord is equal to the product of the parts of the other chord.

6

BE × ED = AE × CE , that is

10 × 3x = 12(2x + 1) ← distribute parenthesis by 12

30x = 24x + 12 ( subtract 24x from both sides )

6x = 12 ( divide both sides by 6 )

x = 2

then

ED = 3X = 3(2) = 6

7

RJ × JP = SJ × JQ , that is

6 × 3x = 4(4x + 1) ← distribute parenthesis by 4

18x = 16x + 4 ( subtract 16x from both sides )

2x = 4 ( divide both sides by 2 )

x = 2

then

RP = RJ + JP = 6 + 3x = 6 + 3(2) = 6 + 6 = 12

6 0
2 years ago
Can someone please help me with this question please (sorry for bad photo quality)
Aleks [24]

Answer:

a) (-1/2,3/2)

Step-by-step explanation:

-3x = x + 2

4x + 2 = 0

4x = -2

x = -1/2

y = -3(-1/2) = 3/2

8 0
3 years ago
Simplify open parentheses x to the two fifths power close parentheses to the 3 sevenths power.
pishuonlain [190]

Answer:

  x^(6/35)

Step-by-step explanation:

The applicable rule of exponents is ...

  (a^b)^c = a^(bc)

__

  (x^{\frac{2}{5}})^{\frac{3}{7}}=x^{\frac{2\cdot 3}{5\cdot 7}}=\boxed{x^{\frac{6}{35}}=\sqrt[35]{x^6}}

3 0
3 years ago
Combining like terms<br><br> simplify the expression<br> -r - 10r
Basile [38]

-r-10r

 -r is = to -1r

 so you have -1r - 10r

 which simplifies to -11r

5 0
4 years ago
Help me out ASAP! why they dont let me post
vesna_86 [32]

Answer:

t=11/13

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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