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Alexus [3.1K]
2 years ago
7

Can someone please give me the (Answers) to this? ... please ... I need help….

Mathematics
1 answer:
bezimeni [28]2 years ago
6 0

Answer:

see explanation

Step-by-step explanation:

2 chords intersecting inside a circle , then the product of the parts of one chord is equal to the product of the parts of the other chord.

6

BE × ED = AE × CE , that is

10 × 3x = 12(2x + 1) ← distribute parenthesis by 12

30x = 24x + 12 ( subtract 24x from both sides )

6x = 12 ( divide both sides by 6 )

x = 2

then

ED = 3X = 3(2) = 6

7

RJ × JP = SJ × JQ , that is

6 × 3x = 4(4x + 1) ← distribute parenthesis by 4

18x = 16x + 4 ( subtract 16x from both sides )

2x = 4 ( divide both sides by 2 )

x = 2

then

RP = RJ + JP = 6 + 3x = 6 + 3(2) = 6 + 6 = 12

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3 years ago
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Strike441 [17]
<span>1. Suppose that a family has an equally likely chance of having a cat or a dog. If they have two pets, they could have 1 dog and 1 cat, they could have 2 dogs, or they could have 2 cats.

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</span><span>2. Describe how to use two coins to simulate which two pets the family has.
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<span>3. Flip both coins 50 times and record your data in a table like the one below.

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Based on the results, I concluded that for Heads, Heads (which could be dogs or cats) there was a 24% chance and for Tails, Tails there was a 26% chance

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</span><span>5. How could you change the simulation to generate data for three pets?
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To flip 3 coins and add more spots on the chart.

I hope that this helps because it took a while to write out. If it does, please rate as Brainliest

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