Question

Use the numbers below to answer the following

Answer 1

Power with a natural exponent.

Definition:

$a^2=a\cdot a\\\\a^3=a\cdot a\cdot a\\\\a^4=a\cdot a\cdot a\cdot a\\\vdots\\a^n=\underbrace{a\cdot a\cdot a\cdot...\cdot a}_{n}$

also

$a^1=a\\\\a^0=1$

$6^1=6\\\\3^2=3\cdot3=9\\\\2^3=2\cdot2\cdot2=8\\\\1^7=1$

therefore

$\huge\boxed{1^7 < 6^1 < 2^3 < 3^2}$