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Fittoniya [83]
3 years ago
10

In base, rate, and percent problems, the word “of” points to this

Mathematics
1 answer:
Marysya12 [62]3 years ago
5 0

Answer:

The word "of" refers to multiplication.

Step-by-step explanation:

Multiplication is what to do in all word problems when we see the word "of"

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1.Solve for w.
iren [92.7K]
Hi there,

1) 
6 + (w - 10) = 5
6 + w - 10 = 5
- 4 + w = 5
w = 5 + 4

Hence, W = 9

2)
2/3 + y - 1/9 = 7/9
5/9 + y = 7/9
y= 7/9 - 5/9

Hence, Y = 2/9

4)
4x - 3/2x - 15/4 = 3/8
32x - 12x - 30 = 3
20x - 30 = 3
20x = 3 + 30
20x = 33

Hence, the answer is 33/20

5)
0.7(3s + 4) - 1.1s = 7.9
2.1s + 2.8 - 1.1 = 7.9
s + 2.8 = 7.9
s = 7.9 - 2.8

Hence, the answer is 5.1

Hope this all helps :)
8 0
3 years ago
Read 2 more answers
. A soccer team played 32 games. If they won 25% of them, how many games did the team win?V
Bas_tet [7]

Answer:

8\ games

Step-by-step explanation:

Let

x----->number of games won by the football team

we know that

25\%=25/100=0.25

so

x=0.25(32)=8\ games

8 0
3 years ago
What are the 2 ways to make 10's and ones out of 28 cubes
andriy [413]
I'm sorry my friend but I need as much help as you do I'm just answering this so I can get some help sorry
8 0
3 years ago
Find all real solutions to the equation (x² − 6x +3)(2x² − 4x − 7) = 0.
Jet001 [13]

Answer:

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ;  x = \frac{2-(3)\sqrt{2}}{2}

Step-by-step explanation:

Relation given in the question:

(x² − 6x +3)(2x² − 4x − 7) = 0

Now,

for the above relation to be true the  following condition must be followed:

Either  (x² − 6x +3) = 0 ............(1)

or

(2x² − 4x − 7) = 0 ..........(2)

now considering the equation (1)

(x² − 6x +3) = 0

the roots can be found out as:

x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

for the equation ax² + bx + c = 0

thus,

the roots are

x = \frac{-(-6)\pm\sqrt{(-6)^2-4\times1\times(3)}}{2\times(1)}

or

x = \frac{6\pm\sqrt{36-12}}{2}

or

x = \frac{6+\sqrt{24}}{2} and, x = x = \frac{6-\sqrt{24}}{2}

or

x = \frac{6+2\sqrt{6}}{2} and, x = x = \frac{6-2\sqrt{6}}{2}

or

x = 3 + √6 and x = 3 - √6

similarly for (2x² − 4x − 7) = 0.

we have

the roots are

x = \frac{-(-4)\pm\sqrt{(-4)^2-4\times2\times(-7)}}{2\times(2)}

or

x = \frac{4\pm\sqrt{16+56}}{4}

or

x = \frac{4+\sqrt{72}}{4} and, x = x = \frac{4-\sqrt{72}}{4}

or

x = \frac{4+\sqrt{2^2\times3^2\times2}}{2} and, x = x = \frac{4-\sqrt{2^2\times3^2\times2}}{4}

or

x = \frac{4+(2\times3)\sqrt{2}}{2} and, x = x = \frac{4-(2\times3)\sqrt{2}}{4}

or

x = \frac{2+3\sqrt{2}}{2} and, x = \frac{2-(3)\sqrt{2}}{2}

Hence, the possible roots are

x = 3 + √6 ; x = 3 - √6 ; x = \frac{2+3\sqrt{2}}{2} ; x = \frac{2-(3)\sqrt{2}}{2}

7 0
3 years ago
If f(x)=2x+7 and g(x)=11x-4, find (f+g)x.
klemol [59]

Answer:

(f+g)(x) = 13x + 3

Step-by-step explanation:

Rewrite  f(x)=2x+7 and g(x)=11x-4 in columns, as follows:

f(x)=2x+7

+g(x)=11x-4

----------------

Now add each column separately.

f(x)+g(x) = (f+g)(x) ("the sum of functions f and g")

2x + 11x = 13x, and, finally, 7-4 = 3.


Therefore,

 f(x)=2x+7

+g(x)=11x-4

----------------

(f+g)(x) = 13x + 3

7 0
3 years ago
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