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galina1969 [7]
3 years ago
5

the sum of the interior angles of the polygon is 20 right angles. how many sides does the polygon have?

Mathematics
1 answer:
Mumz [18]3 years ago
7 0
We have a polygon whose the sum of interior angles is 20 right angles (the measurement of each right angle is 90°), that means
the sum = 20 × 90°
the sum = 1800°

The sum of interior angles on any polygon could be determined using formula
sum = (n - 2) × 180°
n stands for the number of sides the polygon has

sum = (n - 2) × 180°
1800° = (n - 2) × 180°
1800°/180° = n - 2
10 = n - 2
n = 12

The polygon has 12 sides
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son4ous [18]

Answer:

20 cm

Step-by-step explanation:

Shadow of vertical poles : 6m ; 15m

Length of poles : 8cm ; h

8cm long pole = shadow length, 6m

h cm long pole = shadow length, 15 m

Using cross multiplication :

8cm * 15 m = h cm * 6m

120 = 6h

h = 120 / 6

h = 20 cm

Height of second pole = 20cm

8 0
3 years ago
Solve the system of linear equations y= 2x -3Y= x + 6
Alja [10]

Answer:

x=9, y=15. (9, 15).

Step-by-step explanation:

y=2x-3

y=x+6

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2x-3=x+6

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7 0
2 years ago
Finish the polynomial by adding one number to make it a perfect square<br><br> x^2+18x+
dsp73

Answer:

81

Step-by-step explanation:

{x}^{2}  + 18x + {(( \frac{1}{2})(18)) }^{2}

{x}^{2}  + 18x +  {9}^{2}

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6 0
2 years ago
I WILL MARK YOU THE HIGHEST IF RIGHT!!!! NEED HELP ASAP (CANT GET THIS ONE RIGHT.
vitfil [10]
The correct answer is:   [A]:  " 2" . 
_______________________________________________________
Explanation:
_______________________________________________________

5x - 4 = 3x ; 

Subtract "3x" from each side of the equation; 

5x - 4 - 3x = 3x - 3x ; 

2x - 4 = 0 ; 

Add "4" to each side of the equation; 

2x - 4 + 4 = 0 + 4 ; 

2x = 4 ; 

Divide each side of the equation by "2" :

2x / 2  =  4 / 2 ;

  x = 2 ;   which is:  "Answer choice:  [A]:  " 2" . 
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3 0
3 years ago
Given that α and β are the roots of the quadratic equation <img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B6x-7%3Dp" id="Tex
siniylev [52]

Answer:

\large \boxed{\sf \ \ \ p=-11 \ \ \ }

Step-by-step explanation:

Hello,

\alpha \text{ and } \beta \text{ are the roots of the following equation}

   2x^2+6x-7=p

It means that

   2\alpha^2+6\alpha-7=p \\\\2\beta ^2+6\beta -7=p \\\\

And we know that

\alpha= 2\cdot \beta

So we got two equations

   2(2\beta)^2+6\cdot 2 \cdot \beta -7=p \\\\8\beta^2+12\beta -7=p\\\\ and \ 2\beta ^2+6\beta -7=p \ So \\\\\\8\beta^2+12\beta -7 = 2\beta ^2+6\beta -7\\\\6\beta^2+6\beta =0\\\\\beta(\beta+1)=0\\\\ \beta =0 \ or \ \beta=-1

For \beta =0, \ \ \alpha =0, \ \ p = -7

For \beta =-1, \ \ \alpha =-2, \ \ p= 2-6-7=-11, \ p=2*4-12-7=-11

I assume that we are after two different roots so the solution for p is p=-11

b) \alpha +2 =-2+2=0 \ and \ \beta+2=-1+2=1

So a quadratic equation with the expected roots  is

x(x-1)=x^2-x

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

3 0
3 years ago
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