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alukav5142 [94]
2 years ago
5

Help please what is​

Mathematics
1 answer:
dsp732 years ago
3 0

Option A. is correct for the given condition.

Lets solve it through steps of range and functions,

First of all, Solve the equation:
f(x) = |x|+5
= > x = -5 (1)

= > x = 5 (2)

So these would be the ranges of X in between 5 and -5.

Hence option A. R{f(x)eR  [f(x) < 5} is correct.

Learn more about range and functions on:

https://brainly.ph/question/10400053

#SPJ10

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A true-false question is to be posed to a husband and wife team. Both the husband and the wife will give the correct answer with
marysya [2.9K]

Answer:

Choose either strategy both are equally successful

Step-by-step explanation:

Given:-

- The probability of success for both husband (H) and wife (W) are:

                              P ( W ) = 0.8 , P ( H ) = 0.8

Find:-

- Which of the following is a better strategy for the couple?

Solution:-

Strategy 1

- First note that P ( W ) & P ( H ) are independent from one another, i.e the probability of giving correct answer of husband does not influences that of wife's.

- This strategy poses an event such that either wife knows the answer and answer it correctly or the husband knows and answers in correctly.

- We will assume that probability of either the husband or wife knowing the answer is 0.5 and the two events of knowing and answering correctly are independent. So,

                           P ( Wk ) = P (Hk) = 0.5

- The event P(S1) is:

                           P(S1) = P ( Hk & H ) + P ( Wk & W )

                           P(S1) = 0.5*0.8 + 0.5*0.8

                           P(S1) = 0.8

- Hence, the probability of success for strategy 1 is = 0.8

Strategy 2

- Both agree , then the common answer is selected otherwise, one of their answers is chosen at random.

- The success of strategy 2, will occur when both agree and are correct, wife is correct and answers while husband is not or husband is correct and he answers.

- The event P(S2) is:

                   P(S2) = P ( H & W ) + P ( H / W' & Hk ) + P ( H' / W & Wk )

                   P(S2) = P ( H & W ) + P ( H / W') P ( Hk ) + P ( H' / W) P (Wk)

                   P(S2) = P ( H & W ) + P ( H / W')*0.5  + P ( H' / W)*0.5

                   P(S2) = 0.5* [ P ( H & W ) + P ( H / W') ]  + 0.5* [ P ( H' / W) + P ( H & W )]

                   P(S2) = 0.5*P(H) + 0.5*P(W)

                   P(S2) = 0.5*0.8 + 0.5*0.8

                   P(S2) = 0.8

- Hence, the probability of success for strategy 2 is = 0.8

Both strategy give us the same probability of success.

                 

                       

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