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alukav5142 [94]
2 years ago
5

Help please what is​

Mathematics
1 answer:
dsp732 years ago
3 0

Option A. is correct for the given condition.

Lets solve it through steps of range and functions,

First of all, Solve the equation:
f(x) = |x|+5
= > x = -5 (1)

= > x = 5 (2)

So these would be the ranges of X in between 5 and -5.

Hence option A. R{f(x)eR  [f(x) < 5} is correct.

Learn more about range and functions on:

https://brainly.ph/question/10400053

#SPJ10

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Answer:

20 is to 56 as 3 is to x

20x= 8.2

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3 years ago
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Jet001 [13]

Answer:

m= 15 b=25

Step-by-step explanation:

the slope is 15 because thta is the unit rate and the missing point that isnt shown is (0,25)

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3 years ago
6x+18=h(3x+9) what value the constant h in the equation shown below will result in a infinite number of solutions
pav-90 [236]
For there to be an infinite number of solutions, the quantity on the left side of the equation must be the same as on the right.
First, distribute the equation to get 
6x + 18 = 3xh + 9h
If h = 2, the equation on the right would also be 6x + 18 which would yield the same equation and hence an infinite number of solutions
So the answer is h = 2
4 0
3 years ago
Read 2 more answers
Let x be the amount of time (in minutes) that a particular San Francisco commuter must wait for a BART train. Suppose that the d
larisa [96]

Answer:

a) P(X

P(X>14) = 1-P(X

b) P(7< X

c) We want to find a value c who satisfy this condition:

P(x

And using the cumulative distribution function we have this:

P(x

And solving for c we got:

c = 20*0.9 = 18

Step-by-step explanation:

For this case we define the random variable X as he amount of time (in minutes) that a particular San Francisco commuter must wait for a BART train, and we know that the distribution for X is given by:

X \sim Unif (a=0, b =20)

Part a

We want this probability:

P(X

And for this case we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a} = \frac{x-0}{20-0}= \frac{x}{20}

And using the cumulative distribution function we got:

P(X

For the probability P(X>14) if we use the cumulative distribution function and the complement rule we got:

P(X>14) = 1-P(X

Part b

We want this probability:

P(7< X

And using the cdf we got:

P(7< X

Part c

We want to find a value c who satisfy this condition:

P(x

And using the cumulative distribution function we have this:

P(x

And solving for c we got:

c = 20*0.9 = 18

3 0
3 years ago
Suppose r⃗ (t)=cos(πt)i+sin(πt)j+5tkr→(t)=cos(πt)i+sin(πt)j+5tk represents the position of a particle on a helix, where zz is th
gtnhenbr [62]

Answer:

a) t = 4

b) v = pi j + 5 k

c) rt = 1i + (pi t) j + (20 +5t )k

Step-by-step explanation:

You have the following vector equation for the position of a particle:

r(t)=cos(\pi t)\hat{i}+sin(\pi t)\hat{j}+5t\hat{k}    (1)

(a) The height of the helix is given by the value of the third component of the position vector r, that is, the z-component.

For a height of 20 you have:

5t=20\\\\t=\frac{20}{5}=4

(b) The velocity of the particle is the derivative, in time, of the vector position:

v(t)=\frac{dr(t)}{dt}=-\pi sin(\pi t)\hat{i}+\pi cos(\pi t)\hat{j}+5\hat{k}    (2)

and for t=4 (height = 20):

v(t=4)=-\pi sin(\pi (4))\hat{i}+\pi cos(\pi (4))\hat{j}+5\hat{k}\\\\v(t=4)=-0\hat{i}+\pi\hat{j}+5\hat{k}

(c) The vector parametric equation of the tangent line is given by:

r_t(t)=r_o+vt      (3)

ro: position of the particle for t=4

r_o=cos(\pi (4))\hat{i}+sin(\pi (4))\hat{j}+20\hat{k}\\\\r_o=\hat{i}+0\hat{j}+20\hat{k}

Then you replace ro and v in the equation (3):

r_t=(1\hat{i}+20\hat{k})+(\pi \hat{j}+5\hat{k})t\\\\r_t=1\hat{i}+\pi t \hat{j}+(20+5t)\hat{k}

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