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bazaltina [42]
2 years ago
6

Find the area of the rectangle

Mathematics
1 answer:
Hunter-Best [27]2 years ago
5 0

Answer:

<h2>Option A = 1*3 = 3 unit² </h2>

area \: of \: rectangle \:  = length \:  \times breath

length \:  = distance \: between \: f \: and \: g \: or \: between \: e \: and \: h \:

<h3>Distance between f and G = distance between E and H </h3>

F = (3,7)

G = (6,4)

H = (5,3)

E= (2,6)

= (3 units)

<h3>Distance between FE = GH </h3>

= 1 units

Area = 3* 1

= 3 units²

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What is the angle of DBC
Licemer1 [7]
When added, these two angles are supplementary, meaning that their sum is 180. This means that we can do the following to find x, and eventually DBC:

3x+67+4x+50=180
Simplifies to:
7x+117=180
Then by the Subtraction Prop. of Equality:
7x=63
Then divide by 7 on both sides to get that x=9.

We then substitute 9 into angle DBC.
4(9)+50
=36+50
DBC=86

:)

8 0
3 years ago
What is the first integer to the right of 0 on the number line
Nesterboy [21]

Answer:

1

Step-by-step explanation:

Numbers to the "right of 0" implies the positive numbers.  And an integer has no fractional component.  Thus, the first integer to the right of 0 would be 1.

Cheers.

4 0
3 years ago
Need help please I only have a little bit of time
dimaraw [331]

Answer:

A. 7/11

Step-by-step explanation:

5 0
3 years ago
PLEASE HELP ME!!!!!!!!!
vitfil [10]
<h2>1)</h2>

(x - 4) {}^{2}  - 28 = 8 \\ (x - 4) {}^{2}  = 8 + 28 \\ (x - 4) {}^{2}  = 36

This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.

\sqrt{(x - 4) {}^{2} }  =  ± \sqrt{36}  \\x - 4 = ±6 \\ x _{1}- 4 = 6 \:  \:  \:  \:  \:  \:  \: \:  \:  \:  x _{2}- 4 =  - 6 \\ x_{1} = 6 + 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2} =  - 6 + 4 \\ x_{1} = 10 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \: \:  \: x_{2} =  - 2

<h2>2)</h2>

Well he started off correct to the point of completing the square.

(x - 3)  {}^{2}  = 16 \\ x - 3 = ±4 \\  \: x_{1}  - 3 = 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  - 3 =  - 4 \\ x_{1}  = 7 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  =  - 1

8 0
11 months ago
How do you solve for X?<br> BD= 5x+3 AE= 4x+18
Kaylis [27]
Hope this helps :)))

6 0
2 years ago
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