Answer:
12 possibilities
Step-by-step explanation:
In the first urn, we have 4 balls, and all of them are different, as they have different labels, so the group of two red balls r1 and r2 is different from the group of red balls r2 and r3.
The same thing occurs in the second urn, as all balls have different labels.
The problem is a combination problem (the group r1 and r2 is the same group r2 and r1).
For the first urn, we have a combination of 4 choose 2:
C(4,2) = 4!/2!*2! = 4*3*2/2*2 = 2*3 = 6 possibilities
For the second urn, we also have a combination of 4 choose 2, so 6 possibilities.
In total we have 6 + 6 = 12 possibilities.
Break into 2 equatins to get x's:
2x-6<4 and 2x-6>-4
Solve for x in both:
2x-6<4
2x<10
x<5
2x-6>-4
2x>2
x>1
Graph both inequalities on the same number line:
<---0-----1-----2-----3-----4-----5-----6--->
Answer:
0.02
Step-by-step explanation:
5/69.12=0.0723
3/69.12=0.0434
0.0723-0.0434=0.0289
=0.02
ANSWER
The linear equation is: y = 80x + 65
Te cost for 40 football jerseys: $3265
EXPLANATION
Let 'x' be the number of jerseys and 'y' the cost of x jerseys.
Each jersey costs $80, so the cost of x jerseys is 80x. There's also an extra fee for procesing of $65, which is the same no matter how many jerseys they buy.
Therefore, the cost 'y' of x jerseys is:
Now we want to know the cost of 40 football jerseys, so we just have to replace x by 40 and solve:
To solve for x
bx=-7
divide b on both sides
x=-7/b
to solve for b
bx=-7
divide x on both sides
b=-7/x
