Answer:
42 bro
Step-by-step explanation:
Answer:
1/0.7
Step-by-step explanation:
The expression x-y equals to 0.7 so we have to substitute 0.7 in the place of x-y....
----> 1/0.7
Dividing would make this equal to a long division answer (1.42857142857) so let's just leave it as a fraction!
I hope this helps! :)
= 1/2kx2
U = potential energy of a spring at a certain position
k = the spring constant, specific to the spring, with units N/m.
x = distance the spring is stretched or compressed away from equilibrium
Potential Energy: Elastic Formula Questions:
1) A spring, which has a spring constant k = 7.50 N/m, has been stretched 0.40 m from its equilibrium position. What is the potential energy now stored in the spring?
Answer: The spring has been stretched x = 0.40 m from equilibrium. The potential energy can be found using the formula:
U = 1/2kx2
U = 1/2(7.50 N/m)(0.40 m)2
U = 0.60 N∙m
U = 0.60 J
Lwh=v
2*w*(w+2)=48
2w^2+4w=48
w^2+2w-24=0
(w+6)(w-4)=0
w= - 6 or w= 4
Since w cannot be negative, then w=4.