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Ugo [173]
3 years ago
8

Q7 Q24.) Write the vector v in terms of i and j whose magnitude || v || and direction θ are given.

Mathematics
2 answers:
bixtya [17]3 years ago
5 0

i-component: |v|cos(theta)=-14/sqrt(2)=-7sqrt(2)

j-component: |v|sin(theta)=-14/sqrt(2)=-7sqrt(2)

v=-7(sqrt(2))i - 7(sqrt(2))j

 

SIZIF [17.4K]3 years ago
4 0
V=|v|(i cosθ + j sinθ)
=14(i cos225 + j sin225)
=14(-\frac{ \sqrt{2} }{2} i + -\frac{ \sqrt{2} }{2} j)
=(-7\sqrt{2} i + -7\sqrt{2} j)

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Please help! Brainliest to correct.
Margarita [4]

Answer:

We are given the following in the question:

where P(x) in millions is the number of U.S. travelers from 1990 through 2009 and x = 1 represents 1991.

We have to approximate the number of U.S. travelers to other countries in each given year.

​(a) 1990

We put x = 0 in the given function.

Thus, there are 48.09 millions U.S. travelers in 1990.

​(b) 2000

We put x = 10 in the given function.

Thus, there are 56.888 millions U.S. travelers in 2000.

​(c) 2009

We put x = 19 in the given function.

Thus, there are 31.085 millions U.S. travelers in 2009.

Step-by-step explanation:

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7 0
2 years ago
2 7/8 divided by 2 1/4
trasher [3.6K]

2 7/8 = 23/8

2 1/4 =  9/4

23/8 / 9/4 =

23/8 * 4/9 = 92/72 = 1 20/72 =  1 5/18

5 0
3 years ago
Consider the initial value problem y′+2y=4t,y(0)=8.
Xelga [282]

Answer:

Please read the complete procedure below:

Step-by-step explanation:

You have the following initial value problem:

y'+2y=4t\\\\y(0)=8

a) The algebraic equation obtain by using the Laplace transform is:

L[y']+2L[y]=4L[t]\\\\L[y']=sY(s)-y(0)\ \ \ \ (1)\\\\L[t]=\frac{1}{s^2}\ \ \ \ \ (2)\\\\

next, you replace (1) and (2):

sY(s)-y(0)+2Y(s)=\frac{4}{s^2}\\\\sY(s)+2Y(s)-8=\frac{4}{s^2}  (this is the algebraic equation)

b)

sY(s)+2Y(s)-8=\frac{4}{s^2}\\\\Y(s)[s+2]=\frac{4}{s^2}+8\\\\Y(s)=\frac{4+8s^2}{s^2(s+2)} (this is the solution for Y(s))

c)

y(t)=L^{-1}Y(s)=L^{-1}[\frac{4}{s^2(s+2)}+\frac{8}{s+2}]\\\\=L^{-1}[\frac{4}{s^2(s+2)}]+L^{-1}[\frac{8}{s+2}]\\\\=L^{-1}[\frac{4}{s^2(s+2)}]+8e^{-2t}

To find the inverse Laplace transform of the first term you use partial fractions:

\frac{4}{s^2(s+2)}=\frac{-s+2}{s^2}+\frac{1}{s+2}\\\\=(\frac{-1}{s}+\frac{2}{s^2})+\frac{1}{s+2}

Thus, you have:

y(t)=L^{-1}[\frac{4}{s^2(s+2)}]+8e^{-2t}\\\\y(t)=L^{-1}[\frac{-1}{s}+\frac{2}{s^2}]+L^{-1}[\frac{1}{s+2}]+8e^{-2t}\\\\y(t)=-1+2t+e^{-2t}+8e^{-2t}=-1+2t+9e^{-2t}  

(this is the solution to the differential equation)

5 0
3 years ago
Solve for the value of b.<br> 59°<br> (8b+7)°
Blababa [14]

Answer:

b = 3

Step-by-step explanation:

the 2 indicated angles form a right angle and sum to 90° , that is

8b + 7 + 59 = 90

8b + 66 = 90 ( subtract 66 from both sides )

8b = 24 ( divide both sides by 8 )

b = 3

7 0
2 years ago
I need help asap!! if A=3,B=-6 and C=2,which expression would yield the answer of -12?
tester [92]

B2

-6x2=-12

hope it helps

5 0
3 years ago
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