guess you better read the directions and just read the book yourself and find the answer.
Using the python code we can say that it will be possible to calculate the neutrons and organize them as:
<h3>The code can be written as:</h3>
<em>def get_total_derivative(self,l_id):</em>
<em>def sigmoid(x, div = 0):</em>
<em>if div == 1: </em>
<em>return np.exp(-x) / (1. + np.exp(-x))**2.</em>
<em>if div == 2: </em>
<em>return - np.exp(x) * (np.exp(x) - 1) / (1. + np.exp(x))**3.</em>
<em>return 1. / (1. + np.exp(-x)) </em>
<em />
<em>def linear(x, div = 0):</em>
<em>if div == 1: </em>
<em>return np.full(x.shape,1)</em>
<em>if div > 2: </em>
<em>return np.zeros(x.shape)</em>
<em>return x </em>
<em />
<em />
<em />
See more about python at brainly.com/question/18502436
#SPJ1
There are 101 keys on a microsoft windows standard keyboard
Answer:
import java.util.Scanner;
class Main {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
while(true) {
System.out.print("Enter an integer (0 to exit): ");
int num = scan.nextInt();
if (num == 0) break;
if (num%3 == 0 && num%5 == 0) {
System.out.printf("%d is divisable by both 3 and 5.\n", num);
}
else if (num%3 == 0 && num%5 != 0) {
System.out.printf("%d is divisable by 3 but not by 5.\n", num);
}
else if (num%3 != 0 && num%5 == 0) {
System.out.printf("%d is divisable by 5 but not by 3.\n", num);
} else {
System.out.printf("%d is not divisable by 3 or 5.\n", num);
}
}
scan.close();
}
}