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Alinara [238K]
2 years ago
14

assuming the default gateway is connected to the internet, what type of internet access would this server have?

Computers and Technology
1 answer:
erik [133]2 years ago
3 0

If the default gateway is connected to the internet, the type of internet access that the server would have is:

  • Full Access

<h3>What is a Default Gateway?</h3>

A default gateway is a functionality in a computer system that allows access or communication with other networks.

It is the primary channel of interaction with other networks. Once this default gateway is connected to the internet, it will be given full access.

Learn more about the default gateway here:

brainly.com/question/2692918

#SPJ11

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8. Given the array String[] words, which already contains 1 or more values, write a block of code which counts and returns the n
Vikentia [17]

Answer:

Following are the code to this question:

public class Main//defining a class

{

public static void main(String[] arg)//defining main method

{

  String[] words={"Key","day", "Know", "kind"};//defining array of String words

  int x=0;//defining integer variable for count value

  for(int i=0;i<words.length;i++)//defining for loop for count value

  {

 if(words[i].startsWith("k")||words[i].startsWith("K"))//use if block to check word start from k

  x=x+1;//increment the value of x

  }

System.out.print("The number of letters which starts from k is: "+ x);//print value with message

}

}

Output:

The number of letters which starts from k is: 3

Explanation:

In this code, inside the main method an array of String "words" is defined that hold a value, and in the next step an integer variable "x" is defined, which is used to count the letters, which starts from k.

For this, a for loop is used that counts the value and in this an, if block is defined that uses the "startsWith" method to check the value and increment the value of x and at the last, it prints its value.

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3 years ago
Write the definition of a function divide that takes four arguments and returns no value . The first two arguments are of type i
Nastasia [14]

Answer:

#include <iostream>

using namespace std;

void divide(int numerator, int denominator, int *quotient, int *remainder)

{

*quotient = (int)(numerator / denominator);

*remainder = numerator % denominator;

}

int main()

{

int num = 42, den = 5, quotient=0, remainder=0;

divide(num, den, &quotient, &remainder);

 

return 0;

}

Explanation:

The exercise is for "Call by pointers". This technique is particularly useful when a variable needs to be changed by a function. In our case, the quotient and the remainder. The '&' is passing by address. Since the function is calling a pointer. We need to pass an address. This way, the function will alter the value at the address.

To sum up, in case we hadn't used pointers here, the quotient and remainder that we set to '0' would have remained zero because the function would've made copies of them, altered the copies and then DELETED the copies. When we pass by pointer, the computer goes inside the memory and changes it at the address. No new copies are made. And the value of the variable is updated.

Thanks! :)

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when a driver receives a text while driving, what can 2022 versa’s hands-free text messaging assistant do?
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Answer:

It can translate text to voice

Explanation:

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