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lbvjy [14]
3 years ago
13

Christina used the following expression to calculate the average ages of her three program users: average = age1 + age2 + age3 /

3 However, her output is not correct. What did she do wrong?
A.She did not use parentheses around the age values to indicate the proper order of operations.
B.She did not use quotation marks around the age values to indicate the proper order of operations.
C.She should have used the multiplication symbol instead of the division symbol.
D.She should have used a string function to perform the calculation.
Computers and Technology
2 answers:
aleksley [76]3 years ago
6 0
I am thinking it's A. Not so sure though.
Illusion [34]3 years ago
4 0

Only age3 is divided by 3. To calculate the average, you should first add the ages, then divide by the number of ages. This can be accomplished by adding parenthesis around the age values. Answer A is the correct one.

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Write a program that uses nested loop or for statements to display Pattern A below, followed by an empty line and then another s
JulsSmile [24]

Answer:

public class Pyramid {

   public static void main(String[] args) {

             int h = 7;

       System.out.println("Pattern A");

               for(int i = 1; i <= h; ++i)

               {

                   for(int j = 1; j <= i; ++j) {

                       System.out.print("+");

                   }

                   System.out.println();

               }

       System.out.println();

       System.out.println("Pattern B");

               for (int i = 1; i<=h; ++i)

               {

                 for(int j = h; j >=i; --j){

                     System.out.print("+");

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                   System.out.println();

               }

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Explanation:

  • The trick in this code is using a nested for loop
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  • The inner for loop which prints the (+) sign runs from j = 0 to j<=i
  • It prints the + using the print() function and not println()
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Zepler [3.9K]

Answer:

b. Customized auditing.

Explanation:

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There are two types of vulnerability scanning, they are credentialed and non-credentialed scanning and they are defined as implied. The non credentialed scan requires no authorisation and credentials for scanning to take place while credentialed scan is the reverse.

The credentialed scanning provides baseline and customised auditing features.

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3 years ago
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Computer system with a 32-bit logical address and 4k-byte page size. assume that each entry of a page table consists of 4bytes.
Annette [7]

The number of bits in the physical address is 26 bits. The number of entries in a page table is \mathbf{2^{20}} entries. The size of the page table in a one-level paging scheme is 4MB.

<h3>
What is paging in Operating System?</h3>

Paging is a storage method used in operating systems to recover activities as pages from secondary storage and place them in primary memory. The basic purpose of pagination is to separate each procedure into pages.

We are given the following parameters:

  • 32-bit logical address
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  • Size of each Page table entry = 4 bytes

Suppose the system supports physical memory size = 64 MB = \mathbf{2^{26} \ bytes}

Thus, the number of bits in the physical address is computed as:

= \mathbf{log_2 \{Physical-memory-size\}}

=\mathbf{log_2(2^{26})}}

= 26 bits

The number of entries in a page table = logical address space size/page size

The number of entries in a page table \mathbf{= \dfrac{2^{32}}{2^{12}}}

\mathbf{=2^{20}} entries

In a one-level paging scheme, the size of the table is:

= entire no. of page entries × page table size

= \mathbf{2^{20}\times 4 \ bytes}

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b.

suppose that this system supports up to 2^30 bytes of physical memory.

  • The size of the page table will be the same as 4 MB due to the fact that the number of entries, as well as, the page table entry size is the same.

Since the size of the page table surpasses that of a single page. A page cannot include a whole page table. Therefore, the page table must be broken into parts to fit onto numerous pages, and an additional level of the page table is required to access this page table.

  • This is called the Multi-Level Paging system.

Therefore, we can conclude that the number of bits in the physical address is 26 bits, the number of entries in a page table is \mathbf{2^{20}} entries, and the size of the page table in a one-level paging scheme is 4MB.

Learn more about Paging in Operating System here:

brainly.com/question/17004314

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Hi there!

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