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1 year ago

(2a²-a²-7a+2)÷(a-2) Answer Please

Mathematics

1 answer:

ikadub [295]1 year ago

7 0

Answer:

2a^2 + 3a - 1 ,

Step-by-step explanation:

I am assuming you mean

2a^3-a^2-7a+2

By long division:

a - 2 ) 2a^3 - a^2 - 7a + 2 ( 2a^2 + 3a - 1 <------- Quotient

2a^3 - 4a^2

3a^2 - 7a

3a^2 - 6a

-a + 2

. . . . .

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2 years ago

Find the quotient of 3 2/5divided by 4 1/3

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2 years ago

Which two points are on the graph of M(a) = - 3/4a-12?

sertanlavr [38]

Answer:

(-16, 0) and (0,-12) are exactly two points on the graph of the given equation.

Step-by-step explanation:

Here, the given expression is : $M(a) = -\frac{3}{4} a-12$

Here, let M(a) = b

⇒The equation becomes $b = -\frac{3}{4} a-12$

Now, check for all the given points for (a,b)

1) FOR (-9,0)

$RHS is -\frac{3}{4} (-9)-12 = -5.25 \neq 0$

Hence, (-9,0) is NOT on the graph.

2) FOR (-16,0)

Here, LHS = b = 0

and $RHS = -\frac{3}{4} (-16)-12 = 12-12 = 0$

Hence, LHS = RHS = 0 So, (-16,0) is on the graph.

3) FOR (0,12)

Here, LHS = b = 12

$RHS is -\frac{3}{4} (0)-12 = -12 \neq 12$

Hence, (0,12) is NOT on the graph.

4) FOR (0,-12)

Here, LHS = b = -12

$RHS is -\frac{3}{4} (0)-12 = -12$

and LHS = RHS = -12

Hence, (0,-12) is on the graph.

Hence, (-16, 0) and (0,-12) are exactly two points on the graph of the given equation.

6 0

3 years ago

D=a+b+c over ac. If you under stand please help

White raven [17]

You forgot to say what the question actually is !

But I've seen this problem before, in the last few days, here on Brainly.
I think the problem has three parts: 1). Solve the equation for 'a';
2). Solve it for 'b'; and 3). Solve it for 'c'.

I'll slog through that, and I'll try to explain what I'm doing clearly enough
so that eventually, you can do it on your own ... which is really the whole
idea behind this website.

1). Solve the equation for 'a'. That means you have to wind up with something
that says a = everything else.

D = (a + b + c) / c

Split the right side into 3 fractions: D = a/c + b/c + c/c

But c/c =1 , so the equation says D = a/c + b/c + 1

Subtract (b/c +1) from each side: D - b/c - 1 = a/c

Multiply each side by 'c' : Dc - b - c = a
========================

2). Solve the equation for 'b'. That means you have to wind up with something
that says b = everything else.

D = (a + b + c) / c

Split the right side into 3 fractions: D = a/c + b/c + c/c

But c/c =1 , so the equation says D = a/c + b/c + 1

Subtract (a/c +1) from each side: D - a/c - 1 = b/c

Multiply each side by 'c' : Dc - a - c = b
==========================

3). Solve the equation for 'c'. That means you have to wind up with
something that says c = everything else.

D = (a + b + c) / c

Split the right side into 3 fractions: D = a/c + b/c + c/c

But c/c =1 , so the equation says D = a/c + b/c + 1

Subtract 1 from each side: D - 1 = a/c + b/c

The two fractions on the right can be added/combined: D - 1 = (a + b) / c

Multiply each side by 'c' : c(D - 1) = (a + b)

Divide each side by (D - 1) : c = (a + b) / (D - 1)

8 0

3 years ago

Read 2 more answers

(2a²-a²-7a+2)÷(a-2) Answer Please ​

(2a²-a²-7a+2)÷(a-2) Answer Please