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Alja [10]
3 years ago
15

Alan measures the circular floor of a tepee, then calculates that it has an area of 12.56 square yards. What is the floor's diam

eter?
Use 3.14 for pi.


[ ] yards
Mathematics
1 answer:
-BARSIC- [3]3 years ago
5 0
The area of a circle is found by pi*r^2

We can plug in the values we know to solve for the radius.

12.56 = 3.14*r^2

Divide both sides by pi.

12.56/3.14 = r^2

Square root both sides.

r = 2 yards

The diameter of a circle is twice as long as the radius, so the answer is 4 yards.







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Please help and thank you
zvonat [6]
The hexagonal prism has a an equation of volume = base * height.

Since we already know the base is 8 sq feet, we can plug in some values and use x as a missing value

40 = 8 * x
Divide by 8
5 = x

X is equal to 5.
7 0
2 years ago
Brainlest and points need help !!
inn [45]

Answer:

it is C.

Step-by-step explanation:

8 people take up one table and 104/13=8

3 0
3 years ago
Read 2 more answers
Which of these statements is true for f(x) = 4 . (7)*?
guajiro [1.7K]

Answer:

C. The y-intercept is (0, 4).

Step-by-step explanation:

The graph of f(x) = 4 is a straight line parallel to the x-axis passing through the point (0, 4).

6 0
3 years ago
Help me with this please
alina1380 [7]
If you assign variables to the problem, it can make things a lot simpler. Lets say chairs are x and tables are y. Therefore you have:
2x+6y=40 
5x+3y=25
Now you can isolate the variable of one equation and put it into another (it doesn't matter which. I'm going to manipulate the top equation to plug into the bottom one).
2x=40-6y 
x=20-3y
Now I plug into bottom equatioin:
5(20-3y) + 3y=25
100-15y+3y=25
100-12y=25
-12y=-75
y=$6.25
Now you can plug in y in either equation to get x. 
2x+6(6.25)=40
37.5+2x=40
2x=2.5
x=1.25
So it costs $6.25 for each table and $1.25 for each chair. If you think about it, it would make sense for the table to cost more for the chair. 
6 0
3 years ago
Find the value of x.
konstantin123 [22]

Answer:

x= 37.5°

Step-by-step explanation:

∠CBD

= 180° -75° (adj. ∠s on a str. line)

= 105°

∠BCD= ∠BDC (base ∠s of isos. △BCD)

∠BCD= x

∠BCD +∠BDC +∠CBD= 180° (∠ sum of △BCD)

x +x +105°= 180°

2x= 180° -105°

2x= 75°

x= 37.5°

<u>Alternative</u><u> </u><u>working</u><u>:</u>

∠BDA= (180° -75°) ÷2 (base ∠s of isos. △ABD)

∠BDA= 52.5°

∠BDA +∠BDC= 90°

52.5° +x= 90°

x= 90° -52.5°

x= 37.5°

6 0
3 years ago
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