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Shkiper50 [21]
4 years ago
5

Talking to a friend _____.

Computers and Technology
2 answers:
Tanzania [10]4 years ago
6 0

The correct answer is B. can help you see past the emotions of a stressful situation

Explanation:

Talking to a friend or someone you trust is beneficial for your mental or emotional health. Indeed, talking to a friend is one of the most effective ways of dealing with negative emotions or situations such as feeling stressed, demotivated or anxiety. This helps you because by openly expressing your feelings to another person and talking about it you might see the situation from a different perspective which would help you to see past negative emotions and instead focus on positive aspects. Also, advice from other people can help you to know how to deal with stress or negative situations. Thus, talking to a friend "can help you see past the emotions of a stressful situation".

d1i1m1o1n [39]4 years ago
4 0
Physiological
related to a person's health or normal functioning
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1. Write the full forms of the following.
Dmitry_Shevchenko [17]

Answer:

1. A) Language of graphics-oriented.

B) Initial public offering

C)

D) Central processing unit

2A) False

B) True

C) False

D) True

7 0
3 years ago
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in Java programming Design a program that will ask the user to enter the number of regular working hours, the regular hourly pay
iren2701 [21]

Answer:

In Java:

import java.util.Scanner;

public class Main {

public static void main(String[] args) {

 int regularhour,overtimehour;

 float regularpay,overtimepay;

 Scanner input = new Scanner(System.in);

 

 System.out.print("Regular Hour: ");

 regularhour = input.nextInt();

 

 System.out.print("Overtime Hour: ");

 overtimehour = input.nextInt();

 

 System.out.print("Regular Pay: ");

 regularpay = input.nextFloat();

 

 System.out.print("Overtime Pay: ");

 overtimepay = input.nextFloat();

 

 float regulargross = regularhour * regularpay;

 float overtimegross = overtimehour * overtimepay;

 float totalgross = regulargross + overtimegross;

 

 System.out.println("Regular Gross Pay: "+regulargross);

 System.out.println("Overtime Gross Pay: "+overtimegross);

 System.out.println("Total Gross Pay: "+totalgross);

 

}

}

Explanation:

This line declares regularhour and overtimehour as integer

 int regularhour,overtimehour;

This line declares regularpay and overtimepay as float

 float regularpay,overtimepay;

 Scanner input = new Scanner(System.in);

 

This prompts the user for regular hour

 System.out.print("Regular Hour: ");

This gets the regular hour

 regularhour = input.nextInt();

 

This prompts the user for overtime hour

 System.out.print("Overtime Hour: ");

This gets the overtime hour

 overtimehour = input.nextInt();

 

This prompts the user for regular pay

 System.out.print("Regular Pay: ");

This gets the regular pay

 regularpay = input.nextFloat();

 

This prompts the user for overtime pay

 System.out.print("Overtime Pay: ");

This gets the overtime pay

 overtimepay = input.nextFloat();

 

This calculates the regular gross pay

 float regulargross = regularhour * regularpay;

This calculates the overtime gross pay

 float overtimegross = overtimehour * overtimepay;

This calculates the total gross pay

 float totalgross = regulargross + overtimegross;

 

This prints the regular gross pay

 System.out.println("Regular Gross Pay: "+regulargross);

This prints the overtime gross pay

 System.out.println("Overtime Gross Pay: "+overtimegross);

This prints the total gross pay

 System.out.println("Total Gross Pay: "+totalgross);

8 0
3 years ago
In a block of addresses we know the IP address of one host is Roll no. Roll no. Roll no. Roll no./20.What is the first address a
lesya [120]

Answer:

If there’s one topic that trips people up (both new and experienced) in the networking industry, it is that of Subnetting.

One of the reasons this happens is that one has to perform (mental) calculations in decimal and also binary. Another reason is that many people have not had enough practice with subnetting.

In this article, we will discuss what Subnetting is, why it came about, its usefulness, and how to do subnetting the proper way. To make this article as practical as possible, we will go through many examples.

Note: While subnetting applies to both IPv4 and IPv6, this article will only focus on IPv4. The same concepts explained here can be applied to IPv6. Moreover, subnetting in IPv6 is more of a want rather than a necessity because of the large address space.

IP address network

For example, any traffic with a destination IP address of 192.168.1.101 will be delivered to PC1, while traffic addressed to 192.168.1.250 will be delivered to SERVER.

Note: This is an oversimplification of things just for understanding sake and refers to Unicast (one-to-one) IPv4 addresses. Traffic sent to Multicast (one-to-many) and Broadcast (one-to-all) IP addresses can be delivered to multiple devices. Also, features like Network Address Translation (NAT) allow one IP address to be shared by multiple devices.

To help your understanding of IP addresses and subnetting, you need to resolve the following fact in your head: Computers think in binary, that is, 0s and 1s. Therefore, even though we see an IP address represented like 192.168.1.250, it is actually just a string of bits – 32 bits in total for IPv4 addresses.

To make them more readable for humans, IPv4 addresses are represented in dotted decimal notation where the 32 bits are divided into 4 blocks of 8 bits (also known as an octet), and each block is converted to a decimal number.

For example, 01110100 in binary is 116 in decimal:

A unicast IPv4 address such as 192.168.1.250 can be divided into two parts: Network portion and Host ID. So what does this mean? Well, IPv4 addresses were originally designed based on classes: Class A to Class E. Multicast addresses are assigned from the Class D range while Class E is reserved for experimental use, leaving us with Class A to C:

Class A: Uses the first 8 bits for the Network portion leaving 24 bits for host IDs. The leftmost bit is set to “0”.

Class B: Uses the first 16 bits for the Network portion leaving 16 bits for host IDs. The two leftmost bits are set to “10”.

Class C: Uses the first 24 bits for the Network portion leaving 8 bits for host IDs. The three leftmost bits are set to “110”.

Note: The range of Class A is actually 1-126 because 0.x.x.x and 127.x.x.x are reserved.

With these classes, a computer/device can look at the first three bits of any IP address and determine what class it belongs to. For example, the 192.168.1.250 IP address clearly falls into the Class C range.

Looking at the Host ID portion of the classes, we can determine how many hosts (or number of individual IP addresses) a network in each class will support. For example, a Class C network will ideally support up to 256 host IDs i.e. from 00000000 (decimal 0) to 11111111 (decimal 255). However, two of these addresses cannot be assigned to hosts because the first (all 0s) represents the network address while the last (all 1s) represents the broadcast address. This leaves us with 254 host IDs. A simple formula to calculate the number of hosts supported

Explanation: Final answer is Start address: 192.168.58.0 + 1 = 192.168.58.1

End address: 192.168.58.16 – 2 = 192.168.58.14

Broadcast address: 192.168.58.16 – 1 = 192.168.58.15

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802.1x

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