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Mama L [17]
2 years ago
5

Which of the following ordered pairs is a possible solution to the equation y = -2/3x - 4

Mathematics
1 answer:
Karolina [17]2 years ago
6 0

The ordered pair that is the possible solution for the equation is (-6,0) (0,-4).

<h3>What is the Slope-intercept form of a linear equation?</h3>

The slope-intercept form of a linear equation takes the form y= mx + b.

Here:

  • Slope = m
  • b = y-intercept

The function f(x) = y = \mathbf{-\dfrac{2}{3}x-4}

\mathbf{y = -\dfrac{2}{3}x-4}

The slope (m) = -2/3

The x-intercept is the value of x for which y = 0

  • x-intercept = (-6,0)

The y-intercept is the value of y for which x = 0

  • y-intercept = (0,-4)

Learn more about the slope-intercept form of a linear equation here:

brainly.com/question/1884491

#SPJ1

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1. The 95% confidence interval for the difference between means is (-5.34, 11.34).

2. The standard error of (x-bar1)-(x-bar2) is 4.

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{9.2195^2}{10}+\dfrac{9.4868^2}{12}}\\\\\\s_{M_d}=\sqrt{8.5+7.5}=\sqrt{16}=4

Step-by-step explanation:

We have to calculate a 95% confidence interval for the difference between means.

The sample 1, of size n1=10 has a mean of 45 and a standard deviation of √85=9.2195.

The sample 2, of size n2=12 has a mean of 42 and a standard deviation of √90=9.4868.

The difference between sample means is Md=3.

M_d=M_1-M_2=45-42=3

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{9.2195^2}{10}+\dfrac{9.4868^2}{12}}\\\\\\s_{M_d}=\sqrt{8.5+7.5}=\sqrt{16}=4

The critical t-value for a 95% confidence interval is t=2.086.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_{M_d}=2.086 \cdot 4=8.34

Then, the lower and upper bounds of the confidence interval are:

LL=M_d-t \cdot s_{M_d} = 3-8.34=-5.34\\\\UL=M_d+t \cdot s_{M_d} = 3+8.34=11.34

The 95% confidence interval for the difference between means is (-5.34, 11.34).

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