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Papessa [141]
3 years ago
14

1. Write the equation in standard form. Identify the important features of the graph:

Mathematics
1 answer:
NeTakaya3 years ago
6 0

Answer:

  1. (x-4.5)^2 +(y +5)^2 = 30.25
  2. x = (1/8)y^2 +(1/2)y +(1/2)
  3. y^2/36 -x^2/64 = 1
  4. x^2/16 +y^2/25 = 1

Step-by-step explanation:

1. Complete the square for both x and y by adding a constant equal to the square of half the linear term coefficient. Subtract 15, and rearrange to standard form.

  (x^2 -9x +4.5^2) +(y^2 +10y +5^2) = 4.5^2 +5^2 -15

  (x -4.5)^2 +(y +5)^2 = 30.25 . . . . . write in standard form

Important features: center = (4.5, -5); radius = 5.5.

__

2. To put this in the form x=f(y), we need to add 8x, then divide by 8.

  x = (1/8)y^2 +(1/2)y +(1/2)

Important features: vertex = (0, -2); focus = (2, -2); horizontal compression factor = 1/8.

__

3. We want y^2/a^2 -x^2/b^2 = 1 with a=36 and b=(36/(3/4)^2) = 64:

  y^2/36 -x^2/64 = 1

__

4. In the form below, "a" is the semi-axis in the x-direction. Here, that is 8/2 = 4. "b" is the semi-axis in the y-direction, which is 5 in this case. We want x^2/a^2 +y^2/b^2 = 1 with a=4 and b=5.

  x^2/16 +b^2/25 = 1

_____

The first attachment shows the circle and parabola; the second shows the hyperbola and ellipse.

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A metalworker has a metal alloy that is 15​% copper and another alloy that is 75​% copper. How many kilograms of each alloy shou
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48 kilograms of 15 % copper is combined with 72 kilograms of 75 % copper to create 120 kg of a 51​% copper​ alloy

<em><u>Solution:</u></em>

Let "x" be the kilograms of 15 % copper

Then, (120 - x) be the kilograms of 75 % copper

Then, according to question,

"x" kilograms of 15 % copper is combined with (120 - x) kilograms of 75 % copper to create 120 kg of a 51​% copper​ alloy

Thus we frame a equation as:

15 % of x + 75 % of (120 - x) = 51 % of 120

<em><u>Solve the equation for "x"</u></em>

15 \% \times x + 75 \% \times (120-x) = 51 \% \times 120\\\\\frac{15}{100} \times x + \frac{75}{100} \times (120-x) = \frac{51}{100} \times 120\\\\0.15x + 0.75(120-x) = 0.51 \times 120\\\\0.15x + 90 - 0.75x = 61.2\\\\0.6x = 90 - 61.2\\\\0.6x = 28.8\\\\Divide\ both\ sides\ by\ 0.6\\\\x = 48

Thus 48 kilograms of 15 % copper used

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6 d) 2

Step-by-step explanation:

Proportions:

5

7 ⇒ 4

BY ⇒3

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28/3 = 27/3 + 1/3 = 9 1/3

BY = 9 1/3

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12 ⇒ 3

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The total cost of a jacket and a pair of pants was $66.12. If the price of the jacket was $3.26 less than the pair of pants, wha
drek231 [11]

Answer:

The price of the jacket was $31.43

Step-by-step explanation:

Let the cost of a jacket = x

Let the cost of a pair of pants = y

Such that,

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From the conditional statement,

x = y - $3.26..........Equation 2.

Solve both equations simultaneously, using the substitution method

From Equation 2;

x = y - 3.26

Substitute y - 3.26 for x in Equation 1.

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y - 3.26 + y = 66.12

collect like terms

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y= 69.36/2 = $34.69.

Put y = $34.69 in Equation 2. to obtain x

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