Answer:
- Hence, 75.52 percent of the u.s. population had internet access in 2005.
- After 25 years or in the year 2015 89% have internet access.
Step-by-step explanation:
the percent p of the u.s. population with internet access is given by:
25 p-34 t=1378
where t is the number of years after 1990.
- We are asked to find what percent of the u.s. population had internet access in 2005 i.e. we need to find the value of p after 15 years i.e. t=15.
⇒ 25p-34×(15)=1378
⇒ 25p-510=1378
⇒ 25p=1378+510
⇒ 25p=1888
⇒ p=75.52
Hence, 75.52 percent of the u.s. population had internet access in 2005.
- Next we are asked to find in what year will 89% have internet access?
i.e. we have to find the value of t when we are given p=89
⇒ 25×89-34t=1378
⇒ 2225-34t=1378
⇒ 2225-1378=34t
⇒ 847=34t
⇒ or 34t=847
⇒ t=24.9112≈25
Hence after 25 years 89% will have internet access.
i.e. in the year 2015 89% will have internet access.
The 1:3 ratio means that the distance from A to the point is 1/4 of the distance from A to B.
The difference of y-coordinates is 10-8 = 2. 1/4 of that is 2·1/4 = 1/2, so the point of interest will have y-coordinate 8 + 1/2 = 8 1/2. This apparently corresponds to the first selection:
... (6 1/2, 8 1/2)
Y = 9x means each box of the new brand is $9.
<span>So the old brand is $2 per box more. I know you </span>
<span>can do part B now!
Hope that helps!!!!!!!!!</span>
Answer:40
Step-by-step explanation:
On a fair die, each face has a 1/6 chance of landing on each toss.
5 and 6 are the only faces greater than 4, therefore there is a 1/6 + 1/6 = 2/6 chance of the die landing on a number greater than 4 for each toss.
Multiply the probability by the total number of tosses to get the number of tosses that are greater than 4.
120 * (2/6) = 240/6 = 40
Approximately 40 tosses will land on a number greater than 4.
