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irakobra [83]
3 years ago
15

21X 33 check answers with reminders

Mathematics
1 answer:
rosijanka [135]3 years ago
8 0

Answer: 693

it is 693 because...

I couldn't really explain with words so I gave you a step by step of my work.

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HELP PLSSS
Gwar [14]

Answer:

LINE D

Step-by-step explanation:

4 0
3 years ago
Match each point with one of the following fractions: 5/6, 7/12, 1/8, 5/16
adelina 88 [10]
I do not know what point is you trying to find
4 0
3 years ago
The age of a boy is twice that of his sister. five years ago the boy was 3 times the age of his sister. How old is the boy
joja [24]

<em>Answer</em><em>:</em>

<h2><em>2</em><em>0</em><em> </em><em>years</em><em> </em><em>old</em><em>.</em></h2>

<em>Sol</em><em>ution</em><em>,</em>

<em>Let</em><em> </em><em>the</em><em> </em><em>age</em><em> </em><em>of</em><em> </em><em>sister</em><em> </em><em>be</em><em> </em><em>X</em>

<em>Let</em><em> </em><em>the</em><em> </em><em>age</em><em> </em><em>of</em><em> </em><em>boy</em><em> </em><em>be </em><em>2</em><em>x</em>

<em>Now</em><em>,</em>

<em>Five</em><em> </em><em>years</em><em> </em><em>ago</em><em>,</em>

<em>3(x - 5) = 2x - 5 \\ or \: 3x - 15 = 2x - 5 \\ or \: 3x - 2x =  - 5 + 15 \\ x = 10</em>

<em>Again</em><em>,</em>

<em>Repla</em><em>cing</em><em> </em><em>value</em><em>,</em>

<em>age \: of \: boy = 2x \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 2 \times 10 \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = 20</em>

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em>.</em><em>.</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>

7 0
3 years ago
Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed
vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 11-1 = 10.

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have T = 1.812

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{4}{\sqrt{11}} = 1.2060

Now, we multiply T and s

M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8cm

For the upper end of the interval, we add the sample mean and M. So the upper end of the interval here is

L = 97 + 2.19 = 99.19 = 99.2cm

So

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm).

7 0
3 years ago
1. Determine the magnitude of the resultant force acting on the plate and its direction, measured counter-clockwise from the pos
AlexFokin [52]
F1 . . . 100% of it = 900N is in the +x direction.

F2 . . . 70.7% of it (cos45°, 530.3N) is in the +x direction,
and 70.7% of it (sin45°, 530.3N) is in the +y direction.

F3 . . . 80% of it (520N) is in the -x direction,
and 60% of it (390N) is in the +y direction.

Total x-component:  900 + 530.3 - 520  =  1,950.3 N

Total y-component:  530.3 + 390  =  920.3 N

Magnitude of the resultant = √ (x²  +  y²)

                                       = √(1950.3²  +  920.3²)

                                       =  √4,650,070.09

                                       =   2,156.4 N  .

Angle of the resultant, measured counterclockwise
from the +x axis, is 
 
                               tan⁻¹  (y / x)

                         =    tan⁻¹  (920.3 / 1950.3)

                         =    tan⁻¹  (0.4719)

                         =    about    25.3°  .

Caution:
The same fatigue that degrades my ability to READ the question accurately
may also compromise the accuracy of my solutions.  Before you use this
answer for anything, check it, check it, check it !

 
4 0
3 years ago
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