Can someone please help me?
1 answer:
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Answer:
Trapezoid
21 is the perimeter.
24 is the area.
Step-by-step explanation:
Let's do the perimeter first, 8 + 4 = 12.
Now we have to get the side lengths. We can do this by using the Pythagoras Theorem by making an imaginary line to form a right triangle. The lengths are 2 and 4. So, 4 + 16 = 20. Square root of 20 + square root of 20 = ~9
12 + 9 = 21
21 is the perimeter.
Now, let's solve the area. The a is 4, b is 8. So 4 + 8 = 12/2 = 6. The height is 4 so 6 * 4 = 24.
24 is the area.
Hope this helped ya
:)
Sin = - 4/8
Quadrant IV = only cosine is positive
a = height (4)
b = base ( 8^2-4^2=b^2
b = 6.93 @
c = hypothenuse(8)
cos =
/8
tan = - 4/
sec = 1/cos
1/cos = 1/ (
/8)
sec = 8/
csc = 1/sin
1/sin = 1/(-4/8)
csc = - 2
cot = 1/tan
1/tan = 1/(-4/
)
cot = -
/4
Quadrant IV = only cosine is positive
a = height (4)
b = base ( 8^2-4^2=b^2
b = 6.93 @
c = hypothenuse(8)
cos =
/8
tan = - 4/
sec = 1/cos
1/cos = 1/ (
/8)
sec = 8/
csc = 1/sin
1/sin = 1/(-4/8)
csc = - 2
cot = 1/tan
1/tan = 1/(-4/
)
cot = -
/4
Answer:
Step-by-step explanation:
The answer is -1/3