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2 years ago

Simplify (4x^-2 y^3)^3*2x^-4 y

Mathematics

1 answer:

butalik [34]2 years ago

4 0

Simplified answer is:

128y^10/x^10

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A 10 pound bag of grapes costs $14.00. How many pounds of grapes can you get for $7.00?

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3 years ago

the gross monthly salary of a manager is $5875. Calculate her net annual salary after deductions of $976 were made monthly

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Answer:

Her net annual salary is of $58,788

Step-by-step explanation:

The gross monthly salary is the salary earned before deductions are applied.

The net monthly salary is the salary after deductions are applied.

In this problem:

Gross monthly salary of a manager is $5875.

Deductions of $976

So net monthly salary = 5875 - 976 = $4899

Net yearly salary:

An year has 12 months. So

12*$4899 = $58,788

Her net annual salary is of $58,788

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3 years ago

At the beginning of a population study, the population of a large city was 1.65 million people. Three years later, the populatio

Maksim231197 [3]

Answer:

C. 1.8027

Step-by-step explanation:

The exponential population growth model is given by:

$P(t) = P_{0}e^{rt}$

In which P(t) is the population after t years, $P_{0}$ is the initial population and r is the growth rate.

At the beginning of a population study, the population of a large city was 1.65 million people. Three years later, the population was 1.74 million people.

This means that $P_{0} = 1.65, P(3) = 1.74$

Applying this to the equation, we find r. So

$P(t) = P_{0}e^{rt}$

$1.74 = 1.65e^{3r}$

$e^{3r} = \frac{1.74}{1.65}$

$e^{3r} = 1.0545$

Applying ln to both sides

$\ln{e^{3r}} = \ln{1.0545}$

$3r = \ln{1.0545}$

$r = \frac{\ln{1.0545}}{3}$

$r = 0.0177$

$P(t) = 1.65e^{0.0177t}$

What would be the population of the city 5 years after the start of the population study?

This is P(5).

$P(t) = 1.65e^{0.0177t}$

$P(5) = 1.65e^{0.0177*5}$

$P(5) = 1.8027$

So the correct answer is:

C. 1.8027

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