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Aloiza [94]
1 year ago
11

Dedi had a combination lock.To open the lock he started at 37.He made 3 half turns clockwise and 3 quarter turns anticlockwise

Mathematics
1 answer:
Lerok [7]1 year ago
5 0
Turning clockwise means the number increase, and counterclockwise means the number decreases

Therefore your answer is 37 + (3*1/2)-(3*1/4)

= 37.75

Hope this helped :)
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Answer:

I think this is the answer but I am not sure sry if I am wrong

Step-by-step explanation:

2x+y=2

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2x+4y=-10

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2x+8-8x=-10

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8 0
2 years ago
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Solving linear systems of substitution
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Example: 2x+2y=8 and 3y+2x=6
Okay so u first want to put on of the equations into a y= form. So let's use 3y+2x=6. Subtract 2x from both sides. 3y=6-2x divide by 3. Y= 6-2/3x or y= -2/3x + 6. Now just plug this new equation in for Y since "y=" into the other equation.
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3 years ago
A triangular prism is 32 inches long and has a triangular face with a base of 18 inches and a
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1752

Step-by-step explanation:

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1 year ago
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Rewrite the statement in mathematical notation. (Let y be the distance from the top of the ladder to the floor, x be the distanc
In-s [12.5K]

Answer:

\frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}

Step-by-step explanation:

Let L be the length of the ladder,

Given,

x = the distance from the base of the ladder to the wall, and t be time.

y = distance from the base of the ladder to the wall,

So, by the Pythagoras theorem,

L^2 = y^2 + x^2

\implies L = \sqrt{y^2 + x^2},

Differentiating with respect to time (t),

\frac{dL}{dt}=\frac{d}{dt}(\sqrt{x^2 + y^2})

=\frac{1}{2\sqrt{x^2 + y^2}}\frac{d}{dt}(x^2 + y^2)

=\frac{1}{2\sqrt{x^2 + y^2}}(2x\frac{dx}{dt}+2y\frac{dy}{dt})

=\frac{1}{\sqrt{x^2 +y^2}}(x\frac{dx}{dt}+y\frac{dy}{dt})

Here,

\frac{dy}{dt}=-6\text{ ft per sec}

Also, \frac{dL}{dt} = 0           ( Ladder length = constant ),

\implies \frac{1}{\sqrt{x^2 +y^2}}(x(-6)+y\frac{dy}{dt})=0

-6x + y\frac{dy}{dt}=0

y\frac{dy}{dt}=6x

\implies \frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}

Which is the required notation.

8 0
3 years ago
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