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crimeas [40]
3 years ago
11

What is the best description of the acceleration of an object?

Mathematics
1 answer:
shtirl [24]3 years ago
7 0

Answer:

A car's velocity changes from 25 m/s to 20 m/s in 5 seconds.

Step-by-step explanation:

By definition, Acceleration is the rate of change of Velocity of an object.

I.e it is the( final velocity minus initial velocity ) ÷  by the time it took for the velocity to change.

If we observe the choices only one choice gives us all 3 components (final velocity, initial velocity, time taken for velocity to change), which is :

A car's velocity changes from 25 m/s to 20 m/s in 5 seconds.

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Julli [10]
Algebra tiles would not be a good tool to use to factor the trinomial because you would need to drag an x-squared tile, 18 x-tiles, and 80 plus tiles. That is a total of 99 tiles. It would take a lot of time to drag that many tiles on the board and there might not be enough space to hold all of them. You would also need to determine how to arrange all those tiles to make a rectangle. Since 80 is a multiple of 10, you might recognize that 10 and 8 are the factors that add to 18, which would give you the values to use in the X method.
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3 years ago
Solve the inequality:8x+3>2x-15​
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Karl's car went 550 miles on 33 gallons of gas. Which equation does NOT give the correct unit rate, x, in miles per gallon for K
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x = 550 ÷ 33




what are the answer choises

Step-by-step explanation:


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A satellite camera takes a rectangular-shaped picture. The smallest region that can be photographed is a 4-km by 4-km rectangle.
Lesechka [4]
So we know that the formula for the area of a rectangle is A = lw.
Now both the length and width of the rectangle increase at 3 km/s, therefore, A(t) = (3t+l)*(3t+w). Since the initial length = initial width = 4 km, then the initial area = 16 [tex]km^2. We want to know the time when the area is four times its original area, therefore, our new formula is: 4A(t) = (3t+l)*(3t+w). Plugging in our known values we have:

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t =  \frac{4}{3} s

The area is four times its original area after <span>\frac{4}{3} s[/tex]</span>.
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