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1 year ago

How many sets of 5 students can be selected out of 30 students?

Mathematics

2 answers:

podryga [215]1 year ago

7 0

Answer:

142 506

Step-by-step explanation:

here the order does not matter

Then

we the number of sets is equal to the number of combinations.

Using the formula :

the number of sets is 30C5

$C{}^{5}_{30}=\frac{30!}{5!\left( 30-5\right) !}$

$=142506$

asambeis [7]1 year ago

4 0

There are 142506 ways in which 5 students can be selected out of 30 students.

<h3>How can a certain number of individuals be selected using a combination?</h3>

The selection of 5 students out of 30 students can be achieved with the use of combination since the order of selection is not required to be put into consideration.

By using the formula:

$\mathbf{^nC_r = \dfrac{n!}{r!(n-r)!}}$

where;

n = total number of individual in the set = 30
r = number of chosing individuals to be selected = 5

$\mathbf{^nC_r = \dfrac{30!}{5!(30-5)!}}$

$\mathbf{^nC_r = \dfrac{30!}{5!(25)!}}$

$\mathbf{^nC_r = 142506}$

Learn more about combination here:

brainly.com/question/11732255

#SPJ11

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And for this case we want to find this probability:

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And we can find the individual probabilities using the probability mass function

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