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Alex
2 years ago
10

The minimun point on the graph of the equation y=f(x) is -1,-3. What is the minimum point on the graphof the equation y=f(x-5)

Mathematics
1 answer:
kap26 [50]2 years ago
4 0

The minimum point on the graph of the equation y=f(x-5) is (-6, -3)

<h3>How to determine the minimum?</h3>

The initial minimum is given as:

(-1, -3)

The transformation y = f(x - 5) means that:

(x, y) = (x - 5, y)

So, we have:

(x, y) = (-1 - 5, -3)

Evaluate

(x, y) = (-6, -3)

Hence, the minimum point on the graph of the equation y=f(x-5) is (-6, -3)

Read more about transformation at:

brainly.com/question/24850937

#SPJ1

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In the isosceles △ABC m∠ACB=120° and AD is an altitude to leg BC . What is the distance from D to base AB , if CD=4cm?
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If ΔACB is an isosceles triangle, then ∠A ≅ ∠B and AC ≅ CB

Since ∠C = 120° and ∠A + ∠B + ∠C = 180°, then ∠A = 30° and ∠B = 30°

Next, look at ΔADB.  ∠A + ∠D + ∠B = 180°, so ∠A + 90° + 30° = 180° ⇒ ∠A = 30°

Now look at ΔADC.  Since ∠A = 30° in ΔACB, and ∠A = 60° in ΔADB, then ∠A = 30° in ΔADC <em>per angle addition postulate.</em>

Now that we have shown that ΔADB and ΔADC are 30-60-90 triangles, we can use that formula to calculate the side lengths.

CD = 4 cm (given) so AC = 2(4 cm) = 8 cm

Since AC ≅ BC, then BC = 8 cm. Therefore, BD = 4 + 8 = 12 <em>by segment addition postulate.</em>

Lastly, look at ΔBHD.  Since ∠B = 30° and ∠H = 90°, then ∠D = 60°. So, ΔBHD is also a 30-60-90 triangle.

BD = 12 cm, so HD = \frac{12}{2}cm = 6 cm

Answer: 6 cm



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3 years ago
Read 2 more answers
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