The thrust angle is an imaginary line drawn perpendicular to the rear axle's centerline. It compares the direction that the rear axle is aimed with the centerline of the vehicle. It also confirms if the rear axle is parallel to its front axle and that the wheelbase on both sides of the vehicle is the same.
True, you should avoid using power point notes always
Answer:
All the ports in a hub are in the same collision domain and a hub sends frames from one host to all other hosts in the network. This makes it prone to collision and poor network throughput. Just like a network switch, it uses the CSMA/CD protocol to detect collision in its network.
A network switch reduces its collision domain to just a port and sends frames from one host to another using its mac table as a route. This makes the network very efficient with high throughput. It also uses the CSMA/CD protocol to detect collision
Explanation:
Switches and hubs are used in networking to connect computer devices in a network. A hub is an obsolete device networking that broadcast a frame to all other ports or host in the network except for the send host port. This increases the rate of collision as all the ports in a hub share the same collision domain. A switch is an efficient frame switching device in a network, which uses its MAC table to decide and find a destination host.
CSMA/CD is a collision detection protocol used in a network to detect and prevent a collision. With this protocol, a host is able to listen, wait, send and resend frames to prevent a collision.
Answer:
Check the explanation
Explanation:
Keep two iterators, i (for nuts array) and j (for bolts array).
while(i < n and j < n) {
if nuts[i] == bolts[j] {
We have a case where sizes match, output/return
}
else if nuts[i] < bolts[j] {
what this means is that the size of nut is lesser than that of bolt and we should go to the next bigger nut, i.e., i+=1
}
else {
what this means is that the size of bolt is lesser than that of nut and we should go to the next bigger bolt, i.e., j+=1
}
}
Since we go to each index in both the array only once, the algorithm take O(n) time.
