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kondor19780726 [428]
2 years ago
7

In triangle xyz, m∠z > m∠x m∠y. which must be true about △xyz? m∠x m∠z < 90° m∠y > 90° ∠x and∠y are complementary m∠x m

∠y < 90°
Mathematics
1 answer:
Anon25 [30]2 years ago
7 0

m∠X + m∠Y < 90° is true.

<h3>How to solve it?</h3>

XYZ is a triangle.

We have to find the option that is true about △XYZ.

By angle sum property of a triangle,

The sum of all the interior angles of a triangle is always equal to 180°.

So, ∠X + ∠Y + ∠Z = 180°

Given, m∠Z > m∠X + m∠Y.

This implies that ∠Z is greater than the sum of the angles ∠X and ∠Y.

so, ∠X + ∠Y must be less than 90°.

Hence, we can say that ∠X + ∠Y < 90°

To know more about triangles, visit:

brainly.com/question/1968095

#SPJ4

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A system of equations are given to us. And we need to solve them . The given system is

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\implies y = x^2 - 3 \\\\\implies 2x - 3 = x^2 - 3 \\\\\implies x^2 - 2x = 0 \\\\\implies x(x-2) = 0 \\\\\implies\red{ x = 0 , 2 }

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\red{Option\:c} \begin{cases} (0,-3) \\ (2,1) \end{cases}

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