F(3) = 5
where 3 is the input and 5 is the output.
Answer:
D.) Elliott has 212 cans, Amelia has 45 cans
Step-by-step explanation:
257 = x + (5x - 12)
257 = 6x - 13
+13 +13
270 = 6x
/6 /6
45 = x (the amount of Amelia's cans)
257 - 45 = 212 (the amount of Elliott's cans)
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Answer: Our required probability would be 0.70.
Step-by-step explanation:
Since we have given that
Number of players = 14
Number of players have recently taken a performance enhancing drug = 3
Number of players have not recently taken a performance enhancing drug = 14-3=11
Number of members chosen randomly = 5
We need to find the probability that at least one of the tested players is found to have taken a performance enhancing drug.
P(Atleast 1) = 1 - P(none is found to have taken a performance enhancing drug)
So, P(X≥1)=1-P(X=0)

Hence, our required probability would be 0.70.
Using Sine.
Sine = Opposite / Hypotenuse
sin 60° = a / (6√3) But sin60° = √3/2
√3/2 = a/(6√3)
Cross multiply
2*a = 6√3 * √3
2a = 6 * √(3*3)
2a = 6*3
a = 6*3/2
a = 3*3 = 9
Option E.
Hope this helps.
Step-by-step explanation:
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