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Nimfa-mama [501]
2 years ago
10

Marta hopes to have a test average of at least 90 by the end of the marking period. Her grades on the first four tests have been

86, 84, 97 and 89. What is the lowest grade she can receive on her fifth and final test and still have a test average of 90 or higher?
Mathematics
1 answer:
Virty [35]2 years ago
5 0

Answer:

 Marta need to score at least 94 to receive an average of 90 or higher considering all five tests.

Explanation:

 Marks received by Marta in four tests =  86, 84, 97 and 89

 Let mark received in fifth test be x

 We have average of five test is more than or equal to 90

 So we have

    \frac{86+84+97+89+x}{5} \geq 90\\ \\ 86+84+97+89+x\geq 450\\ \\ x\geq 94

 So Marta need to score at least 94 to receive an average of 90 or higher considering all five tests.

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S_A_V [24]

Answer:

c. 24 is a solution

Step-by-step explanation:

Given equation:

\frac{4}{3}=\frac{32}{d}

To test the numbers 22, 23, 24, 25 for the solution.

Solution:

In order to test the given number for the solution, we will plugin each number in the unknown variable d and see if it satisfies the equation.

1) d=22

\frac{4}{3}=\frac{32}{22}

Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

\frac{4}{3}=\frac{32\div 2}{22\div 2}

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The above statement can never be true and hence 22 is not a solution.

2) d=23

\frac{4}{3}=\frac{32}{23}

The fractions can no further be reduced.

The statement can never be true and hence 23 is not a solution.

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Reducing fraction to simplest form by dividing the numerator and denominator by their G.C.F.

\frac{4}{3}=\frac{32\div 8}{24\div 8}

\frac{4}{3}=\frac{4}{3}

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4) d=25

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The statement can never be true and hence 25 is not a solution.

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Answer:

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Step-by-step explanation:

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