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Nimfa-mama [501]
3 years ago
10

Marta hopes to have a test average of at least 90 by the end of the marking period. Her grades on the first four tests have been

86, 84, 97 and 89. What is the lowest grade she can receive on her fifth and final test and still have a test average of 90 or higher?
Mathematics
1 answer:
Virty [35]3 years ago
5 0

Answer:

 Marta need to score at least 94 to receive an average of 90 or higher considering all five tests.

Explanation:

 Marks received by Marta in four tests =  86, 84, 97 and 89

 Let mark received in fifth test be x

 We have average of five test is more than or equal to 90

 So we have

    \frac{86+84+97+89+x}{5} \geq 90\\ \\ 86+84+97+89+x\geq 450\\ \\ x\geq 94

 So Marta need to score at least 94 to receive an average of 90 or higher considering all five tests.

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divide the 735 by 5:

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147 * 3 = 441

147 * 2 = 294
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Solving Quadratic Equations using the Square Root Property
Afina-wow [57]

Answer:

x = -2   or   x = -5

Step-by-step explanation:

You need to complete the square before you can take the square root of both sides.

x^2 + 7x + 10 = 0

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x^2 + 7x = -10

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The x-term coefficient is 7. Half of that is 7/2. Square it to get 49/4. Now we add 49/4 to both sides of the equation.

x^2 + 7x + \dfrac{49}{4} = -10 + \dfrac{49}{4}

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(x + \dfrac{7}{2})^2 = \dfrac{9}{4}

Now we use the square root property, if

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x = \pm \sqrt{k}

x + \dfrac{7}{2} = \pm \sqrt{\dfrac{9}{4}}

x + \dfrac{7}{2} = \pm \dfrac{3}{2}

x + \dfrac{7}{2} = \dfrac{3}{2}   or   x + \dfrac{7}{2} = -\dfrac{3}{2}

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3 years ago
Please help me! I need help with this question.
slega [8]

The congruent statement and the reason why the triangles are congruent is (b) ΔUVZ ≅ ΔVYX, SSS

<h3>How to determine the congruent statement and the reason?</h3>

From the question, we have the following parameters that can be used in our computation:

Triangles = UVZ and VYX

There are several theorems that make any two triangles to be congruent

One of these theorems is the SSS congruent theorem

The SSS congruent theorem implies that the corresponding sides of the triangles in question are congruent

From the question, we can see that the following corresponding sides on the triangles UVZ and VYX have the same mark

UV and VY

UZ and VX

VZ and YX

This implies that these sides are congruent sides

Hence, the congruent statement on the congruency of the triangles is (b) ΔUVZ ≅ ΔVYX and the reason is by SSS

Read more about congruent triangles at

brainly.com/question/1675117

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A manufacturer of processing chips knows that 2\%2%2, percent of its chips are defective in some way. Suppose an inspector rando
kipiarov [429]

The data in the question seems a bit erroneous. I am writing the correct question below:

A manufacturer of processing chips knows that 2%, percent of its chips are defective in some way. Suppose an inspector randomly selects 4 chips for an inspection. Assuming the chips are independent, what is the probability that at least one of the selected chips is defective? Lets break this problem up into smaller pieces to understand the strategy behind solving it.

Answer:

The probability that at least one of the selected chips is defective is 0.0776.

Step-by-step explanation:

The question states that the probability of defective chips is 2% i.e. 0.02. Let p denote the probability of selecting a defective chip so, p = 0.02

An inspector selects 4 chips, which means n=4 and we need to compute the probability that at least one of the selected chips is defective. Let X be the number of defective chips selected. We need to compute P(X≥1) which means either 1, 2, 3 or 4 chips can be defective.

We will use the binomial distribution formula to solve this problem. The formula is:

<u>P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ</u>

where n = total no. of trials

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we have n=4, p=0.02 and q=1-0.02=0.98.

We need to compute P(X≥1) which is equal to:

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A shorter method to do this is to use the total probability theorem:

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3 years ago
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