Step-by-step explanation:
Note: Question does not indicate if probability required is for weight to exceed or below 3000 lbs. So choose appropriate answer accordingly (near the end)
Using the usual notations and formulas,
mean, mu = 3550
standard deviation, sigma = 870
Observed value, X = 3000
We calculate
Z = (X-mu)/sigma = (3000-3550)/870 = -0.6321839
Probability of weight below 3000 lbs
= P(X<3000) = P(z<Z) = P(z<-0.6321839) = 0.2636334
Answer:
Probability that a car randomly selected is less than 3000
= P(X<3000) = 0.2636 (to 4 decimals)
Probability that a car randomly selected is greater than 3000
= 1 - P(X<3000) = 1 - 0.2636 (to 4 decimals) = 0.7364 (to 4 decimals)
The equation x=2t-1 represent the x-coordinate. To get the value of x, substitute t with -1.
That is: x = 2(-1) - 1
= -2-1
= -3
Likewise, the equation y=t∧-3 represent the y-coordinate. Substituting t with -1,
y = (-1)∧-3
= -1
The point that correspond to t=-1 is (-3,-1).
Given:
To find:
The steps to prove the given statement by using the properties of multiplication.
Solution:
We have,
Taking left hand side, we get
(Associative property of multiplication)
Hence proved.
Remove the radical by raising each side to the index of the radical.
x=-1
26/3 (improper fraction) 8.667
