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2 years ago

Camilla thinks that -5 is less than -7 because 5 is smaller than 7.explain why Camilla is correct

1 answer:

6 0

Think of a vertical number line. The positive values count down as we move down this number line. The negative numbers count up, so to speak, as we move down the number line. So we have -1, -2, -3, ... as we move down. This indicates that -5 is <u>not</u> smaller than -7.

Diagram is below.

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Ted likes to run long distances. He can run 20 km in 95 minutes.He wants to know how many kilometers he will go if he runs the s

gladu [14]

You just have to cross multiply. 20 x 285 = 5700. 5700 / 95 = 60.

He will run 60km

5 0

3 years ago

Read 2 more answers

|-17|+1 simplify this

grandymaker [24]

Answer:

18 is the correct answer

I-17 I+1= 17+1=18

4 0

2 years ago

How do you get the perimeter of a triangle, all side are 28 cm?

Alisiya [41]

Perimeter of the triangle, a+b+c

In this case, a=b=c=28

So, perimeter would be 28*3 = 84 cm

7 0

2 years ago

A computer system uses passwords that are six characters, and each character is one of the 26 letters (a–z) or 10 integers (0–9)

Blababa [14]

First of all, since we have 36 characters available per spot (26 letters and 10 digits), and we have 6 spots, we have a total of

$36^6$

possible passwords.

Event A happens if the password starts with either a, e, i, o or u. If we fix the first character, we're left with 36 characters available for each of the remaining 5 spots, leading to a total of

$5\cdot 36^5$

possible passwords.

So, the probability of event A, computed as the ratio between "good" cases and all possible cases, is

$\dfrac{5\cdot 36^5}{36^6}=\dfrac{5}{36}$

Event B works exactly the same, since we're fixing the last spot, leaving 36 characters available for each of the first 5 spots. So, we have

$P(A)=P(B)=\dfrac{5}{36}$

As for the intersection, we want the first character to be a vowel, and the last character to be an even digits. There are 25 passwords satisfying this request:

$axxxx0,\ axxxx2,\ axxxx4,\ axxxx6,\ axxxx8$

$exxxx0,\ exxxx2,\ exxxx4,\ exxxx6,\ exxxx8$

$ixxxx0,\ ixxxx2,\ ixxxx4,\ ixxxx6,\ ixxxx8$

$oaxxxx0,\ oxxxx2,\ oxxxx4,\ oxxxx6,\ oxxxx8$

$uxxxx0,\ uxxxx2,\ uxxxx4,\ uxxxx6,\ uxxxx8$

Where x can be any of the 36 characters.

So, we have 25 cases with 4 vacant slots, leading to a probability of

$P(A\cap B)=\dfrac{25\cdot 36^4}{36^6}=\dfrac{25}{1296}$

Finally, you can compute the probability of the union using the formula

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Since we already computed all these quantities.

7 0

2 years ago

To test if the mean IQ of employees in an organization is greater than 100, a sample of 30 employees is taken and the value of t

ivolga24 [154]

Answer:

$p_v =P(t_{(29)}>1.42)=0.0831$

For this case the p value calculated is higher than the significance level used of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

a) do not reject the null hypothesis and conclude that the mean IQ is not greater than 100

Step-by-step explanation:

Information given

We want to verify if he mean IQ of employees in an organization is greater than 100 , the system of hypothesis would be:

Null hypothesis: $\mu \leq 100$