Lysozymes is the correct answer.
Answer: p2 + 2pq + q2 = 1
p2 = homozygous dominant gene
2pq = heterozygous gene
q2 = homozygous recessive gene
Answer:
One-half of the daughters of an affected man would have this condition.
Explanation:
Each daughter born to a woman that is positive for a dystrophin mutation on one of her two X chromosomes possess a 50 percent likelihood of possessing the mutation and also becoming a carrier. Carriers at times do not show the disease symptoms but may give birth to a child that has the mutation or the disease condition. DMD carriers do have a higher chance of cardiomyopathy.
A man with DMD cannot transfer the affected gene to his sons since he passes to his son a Y chromosome, not the X chromosome. But he will definately transfer it to his daughters, since each daughter possess her father’s only X chromosome resulting in the daughters being carriers.
Hence, One-half of the daughters of an affected father and a carrier mother could have this condition.
