Ask question

Ask question

All categories

2 years ago

6

8. If a conditional is true and its hypothesis is true, then its_____ is true.

1 answer:

barxatty [35]2 years ago

5 0

Answer: Conclusion

If a conditional is true and its hypothesis is true, then its conclusion is true.

You might be interested in

After collecting the variables on the left side of the equation, the coefficient of the x term will be?

Kipish [7]

Answer:

56

Step-by-step explanation:

3 0

3 years ago

In a scale drawing of Samantha's apartment, the ratio is 1 in = 3 ft. The length of the living room on the drawing is 6 in and t

erastova [34]

First, multiply 6 in by 3 to get 18 ft as the length of the living room.
6•3=18

Next, multiply 5 in by 3 to get 15 ft as the width of the living room.
5•3=15

Then multiply 18 by 2 and 15 by 2 and add the products together.
(18•2)+(15•2)=66

This makes the answer 66 ft.

3 0

3 years ago

Please help :> 1 mL = 1 cubic meter. How many cubic centimeters are in an 8.00oz bottle of cough medicine. (1.00oz=29.6mL) I'

STatiana [176]

Hope this helps...I couldn't give the exact answer in sig figs because you did not specify how many sig figs you wanted in the answer.

6 0

3 years ago

Over the past several years, the owner of a boutique on Aspen Avenue has observed a pattern in the amount of revenue for the sto

Sidana [21]

Answer:

$f(x)=8500\sin\left(\frac{\pi}{6}\left(x-1\right)\right)+33500$

Step-by-step explanation:

Given information:

Maximum revenue = 42000

Minimum revenue = $25000

Time period = 12 months

We need to write a function that models the boutique's revenue during the year, where corresponds to the month.

$f(x)=Asin(B[x-C])+D$ .... (1)

where, A is amplitude, $\frac{2\pi}{B}$ is period, C is phase shift and D is midline.

$A=Amplitude =\frac{Maximum-Minimum}{2}\Rightarrow \frac{42000-25000}{2}=8500$

$D=midline =\frac{Maximum+Minimum}{2}\Rightarrow \frac{42000+25000}{2}=33500$

$Period=\frac{2\pi}{B}$

$12=\frac{2\pi}{B}\Rightarrow B=\frac{\pi}{6}$

Substitute the value of A, B and D in equation (1).

$f(x)=8500\sin\left(\frac{\pi}{6}\left(x-C\right)\right)+33500$ ..... (2)

In April, revenue of the store is $42000. So, the graph passes through the point (4,42000).

$42000=8500\sin\left(\frac{\pi}{6}\left(4-C\right)\right)+33500$

$42000-33500=8500\sin\left(\frac{\pi}{6}\left(4-C\right)\right)$

$8500=8500\sin\left(\frac{\pi}{6}\left(4-C\right)\right)$

Divide both sides by 8500.

$1=\sin\left(\frac{\pi}{6}\left(4-C\right)\right)$

$\sin \frac{\pi}{2}=\sin\left(\frac{\pi}{6}\left(4-C\right)\right)$

On comparing both sides we get

$\frac{\pi}{2}=\frac{\pi}{6}(4-C)$

$3=4-C$

$C=4-3$

$C=1$

Substitute the value of C in equation (2).

Therefore, the required function is $f(x)=8500\sin\left(\frac{\pi}{6}\left(x-1\right)\right)+33500$ .

5 0

3 years ago

The countin numbers and their opposites, along wit zero are ?

oee [108]

Answer:

is there more to the problem?

Step-by-step explanation:

6 0

4 years ago