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____ [38]
3 years ago
6

A newspaper reports the following changes in the temperature of a city over 4 days:

Mathematics
1 answer:
Pie3 years ago
6 0

Answer:

The expression to show the average daily change in temperature can be given by :

⇒ \frac{2.64-0.22-0.35+0.63}{4}°C

Step-by-step explanation:

Changes in the temperature of city as reported by newspaper :

Day 1: 2.64° C

Day 2: -\frac{2}{9}°C

Day 3: -0.35°C

Day 4: \frac{5}{8}°C

The average daily change in temperature can be calculated as

⇒ \frac{2.64-\frac{2}{9}-0.35+\frac{5}{8}}{4}°C

The fractions can be written in decimals

⇒ \frac{2.64-0.22-0.35+0.63}{4}°C

⇒ \frac{2.7}{4}°C

⇒ 0.675\°C\approx 0.68°C [Average daily change in temperature.]

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Three more than twice a number is nine

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Three more would be + 3

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2 years ago
Need help finding the x, y, and z. please and thank you
Reptile [31]

The first step in any problem is to look at what you are given. When solving systems of linear equations, it is often helpful to eliminate one or more of the variables by adding or subtracting a multiple of one equation with a multiple of another. It is convenient when at least one of the multipliers is 1.

Here, we can cancel the y-terms in the 2nd and 3rd equations simply by adding them together. This gives

... (5x +y -4z) +(-3x -y +5z) = (41) +(-45)

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Likewise, we can add 3 times the second equation to the first to cancel y in that sum.

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Now that we have 2 equations in x and z, we can go through the same process. We observe that the coefficient of z is +1 in the first equation and -11 in the second. The means we can cancel the z terms by adding 11 times the first equation to the second:

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From above, we find

... z = -4 -2x = -4 -2·2 = -8

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_____

The method of elimination used here will vary with the system of equations. If you want to employ a consistent method, you can use Cramer's Rule, Gaussian elimination, or matrix methods. Since you apparently don't mind help from technology, learning to do this on your graphing calculator can also be a good idea.

4 0
2 years ago
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