Let X = the 29% alloy and Y = the 60% alloy.
They want a total of 80kg, so you have X +Y = 80
Rewrite that to get X = 80-Y
You also want 0.20X + 0.60Y = 0.52(80)
Replace X with 80-y:
0.20(80-y) + 0.60y = 0.52(80)
Simplify:
16 - 0.20y + 0.60y = 41.6
Combine like terms:
16 +0.40y = 41.6
Subtract 16 from each side:
0.40y = 25.6
Divide both sides by 0.40
y = 25.6 / 0.40
y = 64
Now you have Y replace y with 80 in X = 80-Y
X = 80 - 64
X = 16
They need 64 Kg of the 60% alloy and 16 Kg of the 20% alloy.
Answer:
+3.8 to each side
Step-by-step explanation:
The reason why Fiona cannot make a valid prediction based on the mean of the population is that the variation of Fiona’s samples is too large.
<h3>Why can't Fiona use the means she recorded?</h3><h3 />
Mean is quite sensitive to outliers so it is best used when the variation between variables is not too much.
In Fiona's case, there variation is quite high with high variable of 95 compared to a low value of 45.
Find out more on effect of outliers at brainly.com/question/16815987.
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Initial balance, I = $2376.10 .
Total amount of purchase made, A = $( 875.22+65.75+45.22+21.23 ) = $1007.42 .
Total amount credit, c = $875.22 .
Fine, f = $45.30 .
Another purchase,
.
So, balance left is :
B = I - A - f - a + c
B = 2376.10 - 1007.42 - 45.30 - 59.4025 + 875.22
B = $2139.1975
Hence, this is the required solution.
We know that 2x + 5 = 10 - 3x, and because of this we can solve for x.
2x + 5 = 10 - 3x
+3x
5x + 5 = 10
-5
5x = 5
/5
x = 1
We can plug x into each x value to verify if this is true.
2(1) + 5 = 10 - 3(1)
2 + 5 = 10 - 3
7 = 7