Consider (cosine (startfraction pi over 2 endfraction) = i sine (startfraction pi over 2 endfraction) ) and z = 3 (cosine (start
1 answer:
Sum of given complex numbers in polar form cos(pi/2) + i.sin(pi/2)
Complex number:
"The number of the type a + ib is called as complex number, where a, b are real numbers and
What is polar form of the complex number?
"The polar form of a complex number z = x + iy
For given question,
The sum of given complex numbers would be w+z = 4cos(pi/2 + i sin(pi/2)+ 3 cos (3pi/2) + i sin(pi/2)
We know that:
cos(pi/2)= 0
sin(pi/2)=1
cos(3pi/2)=0
So, the sum of given complex numbers would be w+z:
=> 4cos(pi/2 + i sin(pi/2)+ 3 cos (3pi/2) + i sin(pi/2)
=> 4i + 3(-i)
= i
= 0+i
Therefore, the sum of given complex numbers in polar form as:
cos(pi/2) + i.sin(pi/2)
Learn more about Complex Numbers here:
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Answer: 2.92
I hope this helped!
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