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Zepler [3.9K]
2 years ago
5

Você tem $ 20 para gastar com o táxi. A corrida custa $5 mais $2,50d 2,50 por quilômetro.

Mathematics
1 answer:
Aloiza [94]2 years ago
5 0

Answer:

$5 + 2.50k ≤ $20

6 kilometers

Step-by-step explanation:

Puedes viajar con $15 porque gastaste 5 en la tarifa base. 15 dividido por 2,5 es 6, por lo que puedes viajar 6 kilómetros con $20.

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Jacob’s recipe calls for 4 7/8 cups of raisins. He has 6/11 of the amount that he needs.
boyakko [2]
If you would like to know how many cups of raisins does Jacob have, you can calculate this using the following steps:

6/11 ... 1/2
4 7/8 cups ... 5 cups

1/2 of 5 cups = 1/2 * 5 = 5/2 = 2 1/2 cups

The correct result would be C. 2 1/2.
8 0
3 years ago
Please I need help with this math homework ASAP thank you!
Montano1993 [528]

Answer:

4

\sqrt{4}  = 2 \\  \\  \sqrt{2}  \times  \sqrt{8 }  =  \sqrt{16}  \\  \\  \sqrt{16}  = 4

4 0
3 years ago
Michael is 12 years older than Brandon. Seventeen years ago, Michael was 4 times as old as Brandon.
4vir4ik [10]

Answer:

21 yrs old

Step-by-step explanation:

m= michael age

b=Brandon age

m=b+12

m-17=4(b-17)= 4b-68 --»»m = 4b -51

//put b+12 instead m// b+12=4b-51

3b=63 --»»b=21

Brandon age is 21

Michael age is 33

3 0
3 years ago
Read 2 more answers
Please answer it for me or show me how to do it? I will mark you branliast answer !!
klasskru [66]

Answer:

25

Step-by-step explanation:

If HI and IJ are both the same and meet at the same point, the triangles would be the same.

7 0
4 years ago
When a bactericide is added to a nutrient broth in which bacteria are​ growing, the bacteria population continues to grow for a​
baherus [9]

Answer:

a)  1296 bacteria per hour

b) 0 bacteria per hour

c) -1296 bacteria per hour

Step-by-step explanation:

We are given the following information in the question:

The size of the population at time t​ is given by:

b(t) = 9^6 + 6^4t-6^3t^2

We differentiate the given function.

Thus, the growth rate is given by:

\displaystyle\frac{db(t)}{dt} = \frac{d}{dt}(9^6 + 6^4t-6^3t^2)\\\\= 6^4-2(6^3)t

a) Growth rates at t = 0 hours

\displaystyle\frac{db(t)}{dt} \bigg|_{t=0}= 6^4-2(6^3)(0) = 1296\text{ bacteria per hour}

b) Growth rates at t = 3 hours

\displaystyle\frac{db(t)}{dt} \bigg|_{t=3}= 6^4-2(6^3)(3) = 0\text{ bacteria per hour}

c) Growth rates at t = 6 hours

\displaystyle\frac{db(t)}{dt} \bigg|_{t=6}= 6^4-2(6^3)(6) = -1296\text{ bacteria per hour}

3 0
4 years ago
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