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Lina20 [59]
2 years ago
11

If (x – 3)(x + 5) = 49, then what is the value of the expression (x – 4)(x + 6)?

Mathematics
1 answer:
mina [271]2 years ago
7 0
It’s impossible to do this because…….. so that’s why it’s impossible
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Sarah is carrying out a series of experiments which involve using mcreasing amounts of a chemical. In the
Marianna [84]

Sarah is carrying out a series of experiments which involve using increasing amounts of a chemical. In the  first experiment she uses 6g of the chemical and in the second experiment she uses 7.8 g of the chemical

(i)Given that the amounts of the chemical used form an arithmetic progression find the total amount of  chemical used in the first 30 experiments

(ii)Instead it is given that the amounts of the chemical used for a geometric progression. Sarah has a  total of 1800 g of the chemical available. Show that the greatest number of experiments possible satisfies the inequality: 1.3^N \leq 91 and use logarithms to calculate the value of N.

Answer:

(a)963 grams

(b)N=17

Step-by-step explanation:

(a)

In the first experiment, Sarah uses 6g of the chemical

In the second experiment, Sarah uses 7.8g of the chemical

If this forms an arithmetic progression:

First term, a =6g

Common difference. d= 7.8 -6 =1.8 g

Therefore:

Total Amount of  chemical used in the first 30 experiments

S_n=\dfrac{n}{2}[2a+(n-1)d] \\S_{30}=\dfrac{30}{2}[2*6+(30-1)1.8] \\=15[12+29*1.8]\\=15[12+52.2]\\=15*64.2\\=963$ grams

Sarah uses 963 grams in the first 30 experiments.

(b) If the increase is geometric

First Term, a=6g

Common ratio, r =7.8/6 =1.3

Sarah has a total of 1800 g

Therefore:

Sum of a geometric sequence

S_n=\dfrac{a(r^N-1)}{r-1} \\1800=\dfrac{6(1.3^N-1)}{1.3-1} \\1800=\dfrac{6(1.3^N-1)}{0.3}\\$Cross multiply\\1800*0.3=6(1.3^N-1)\\6(1.3^N-1)=540\\1.3^N-1=540\div 6\\1.3^N-1=90\\1.3^N=90+1\\1.3^N=91

Therefore, the greatest possible number of experiments satisfies the inequality

1.3^N \leq 91

Next, we solve for N

Changing 1.3^N \leq 91 to logarithm form, we obtain:

N \leq log_{1.3}91\\N \leq \dfrac{log 91}{log 1.3}\\ N \leq  17.19

Therefore, the number of possible experiments, N=17

3 0
3 years ago
A basketball costs $15.00. If the sales tax is 6%, which equation can be used to find the amount of tax?
Andreyy89

Answer:

Tax amount = $15.00 x 0.06 =0.9

Total amount of the basketball = $15.00 x 1.06 = $15.90

6 0
3 years ago
Which value of a will the equation 3x - 2 = 3x - a have an infinite number of solutions?
Dmitrij [34]
It’s A number 2....................../
7 0
3 years ago
A boy's age in ten year time will be four times his age five years ago. Find his present age. ​
Katyanochek1 [597]

Answer:

He is ten.

Step-by-step explanation:

10 yrs old. Go ahead 10 yrs to make 20. Which is four times as much as five years old. (Which is 5 years before 10)

Hope this helps! :)

8 0
3 years ago
If p varies directly as<br> the cube of q, and p =<br> 26 when q = 2, find p<br> when q = 5
Sav [38]

Answer:

The value of p at q = 5 is 406.25

Step-by-step explanation:

∵ p varies directly as the cube of q

→ That means p ∝ q³

∴ The equation of variation is p = kq³, where k is the constant of variation

∵ p = 26 when q = 2

→ Use them to find the value of k

∵ 26 = k(2)³

∴ 26 = k(8)

∴ 26 = 8k

→ Divide both sides by 8

∴ \frac{26}{8}=\frac{k}{8}

∴ 3.25 = k

→ Substitute it in the equation of variation

∴ p = 3.25 q³ ⇒ equation of variation

∵ q = 5

→ Substitute it in the equation of variation to find p

∴ p = 3.25 (5)³

∴ p = 406.25

∴ The value of p at q = 5 is 406.25

7 0
3 years ago
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