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Kryger [21]
3 years ago
9

Lidocaine (2 grams) was prescribed in 500 mL of fluid at 2 mg/ minute, to be administered via an infusion pump. What is the flow

rate?
Mathematics
1 answer:
Luden [163]3 years ago
3 0

9514 1404 393

Answer:

  1/2 mL/min

Step-by-step explanation:

  \dfrac{2\text{ mg}}{\text{min}}\div\left(\dfrac{2\text{ g}}{500\text{ mL}}\times\dfrac{1000\text{ mg}}{\text{g}}\right)=\dfrac{2\times500\text{ mL}}{2\times1000\text{ min}}=\boxed{\dfrac{1}{2}\text{ mL/min}}

__

<em>Additional comment</em>

The units analysis tells you how to work this problem. In order to get from mg/min to mL/min, you need to multiply by a factor with units mL/mg. Those units are the inverse of the concentration in mg/mL, which is found from g/mL.

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He rides his skateboard for 13/15 miles to keep a good speed, he pedals his foot every 4/15 of a mile. How many times does he ha
Deffense [45]

The answer is 6/45. Ask photomath

4 0
4 years ago
(a) How many integers from 1 through 1,000 are multiples of 2 or multiples of 9?
DENIUS [597]

Answer:

(a)There are 500 integers from 1 through 1,000 are multiples of 2.

There are 111 integers from 1 through 1,000 are multiples of 9.

(b)0.611

Step-by-step explanation:

Given the set of Integers from 1 through 1000

The least multiple of 2 is 2 and the highest multiple of 2 in the interval is 1000.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 2,4,6,... is an Arithmetic Progression,

where first term, a =2, common difference, d =2

Nth term of an A.P,

U_n= a+(n-1)d\\1000=2+2(n-1)\\1000=2+2n-2\\1000=2n\\n=500

  • There are 500 integers from 1 through 1,000 are multiples of 2.

Similarly,

Given the set of Integers from 1 through 1000

The least multiple of 9 is 9 and the highest multiple of 9 in the interval is 999.

To determine the number of terms, we use the formula for the nth term of an Arithmetic Progression, since 9,18,27,... is an Arithmetic Progression,

where first term, a =9, common difference, d =9

Nth term of an A.P,

U_n= a+(n-1)d\\999=9+9(n-1)\\999=9+9n-9\\999=9n\\n=111

  • There are 111 integers from 1 through 1,000 are multiples of 9.

(b)Probability that an integer selected at random is a multiple of 2 or a multiple of 9.

There are a total of 1000 numbers between from 1 through 1,000

n(S)=1000

n(Multiples of 2)=500

n(Multiples of 9)=111

Therefore:

P(\text{Multiples of 9}) \:OR\: P(\text{Multiples of 2})=\frac{111}{1000} + \frac{500}{1000} \\=\frac{611}{1000} \\=0.611

7 0
3 years ago
Given csc A= 37/12 and that angle A is in Quadrant I, find the exact value of sec A in
vredina [299]

Answer:

Step-by-step explanation:

Below is the pic of how this would be set up in order to determine what it is you are looking for. The angle is set in QI, and since csc A is the reciprocal of sin, the ratio is hypotenuse over side opposite. Solve for the missing side using Pythagorean's Theorem:

37^2=12^2+b^2 and

1369 = 144 + b² and

1225 = b² so

b = 35

The sec ratio is the reciprocal of cos, so if cos is adjacent over hypotenuse, the sec is hypotenuse over adjacent, which is 37/35

7 0
3 years ago
I really need help with these questions, i don’t even have a clue how to do these.
Anuta_ua [19.1K]

Answer:

231

Step-by-step explanation:

because the whole circle has an area of 360 so on the right side there is half and a little more so you would cut it in half so you have 180 and on the right side you still have a little left so thats about 10 so now you have 190 then you add 21 +20 you have 41 +190 =231 hope this helps

3 0
3 years ago
A television and DVD player cost a total of $1230. The cost of the television is two times the cost of the DVD player. Find the
nikitadnepr [17]

Answer:

Television = 820

DVD Player = 410

Step-by-step explanation: Imagine the television  as 2, and the DVD player as 1. If you’re were to draw it out with boxes, you’d see that the tv  has two boxes and the DVD player has 1 box. All are exactly the same amount, and there are a total of three boxes. So divided 1230 by 3 and you get 410. Using the idea of the boxes, the DVD player get’s one 410, and the tv gets two 410s, or 820.

6 0
3 years ago
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