A boy's age in ten year time will be four times his age five years ago. Find his present age.
1 answer:
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f(0) = 2(3)(0) = 0 ⇒ (0, 0)
f(1) = 2(3)(1) = 6 ⇒ (1, 6)
<u>rate of change from x = 0 to x = 1</u>
=
=
= 6
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f(2) = 2(3)(2) = 12 ⇒ (2, 12)
f(3) = 2(3)(3) = 18 ⇒ (3, 18)
<u>rate of change from x = 2 to x = 3</u>
=
=
= 6
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Since it is the same line, they will have the same slope (aka rate of change).