Answer:
- Calcium binds to troponin C
- Troponin T moves tropomyosin and unblocks the binding sites
- Myosin heads join to the actin forming cross-bridges
- ATP turns into ADP and inorganic phosphate and releases energy
- The energy is used to impulse myofilaments slide producing a power stroke
- ADP is released and a new ATP joins the myosin heads and breaks the bindings to the actin filament
- ATP splits into ADP and phosphate, and the energy produced is accumulated in the myosin heads, starting a new cycle
- Z-bands are pulled toward each other, shortening the sarcomere and the I-band, producing muscle fiber contraction.
Explanation:
In rest, the tropomyosin inhibits the attraction strengths between myosin and actin filaments. Contraction initiates when an action potential depolarizes the inner portion of the muscle fiber. Calcium channels activate in the T tubules membrane, releasing <u>calcium into the sarcolemma.</u> At this point, tropomyosin is obstructing binding sites for myosin on the thin filament. When calcium binds to troponin C, troponin T alters the tropomyosin position by moving it and unblocking the binding sites. Myosin heads join to the uncovered actin-binding points forming cross-bridges, and while doing so, ATP turns into ADP and inorganic phosphate, which is released. Myofilaments slide impulsed by chemical energy collected in myosin heads, producing a power stroke. The power stroke initiates when the myosin cross-bridge binds to actin. As they slide, ADP molecules are released. A new ATP links to myosin heads and breaks the bindings to the actin filament. Then ATP splits into ADP and phosphate, and the energy produced is accumulated in the myosin heads, which starts a new binding cycle to actin. Finally, Z-bands are pulled toward each other, shortening the sarcomere and the I-band, producing muscle fiber contraction.
Answer:
The correct answer is B. 1, 2, and 4
Explanation:
Option no 1 is true because before maturity, the mosquitoes will not be able to cause malaria and will be easier to kill.
Option no 2 is true because in order to ensure a safe control, the Brachiola gambiae shouldn't be dangerous to other animals or insects.
Option No 3 is not true because Mosquito larvae will contain the male larvae also. As the male larvae are not harmful, hence their growth shouldn't be stopped or they should not be killed.
Option No 4 is correct because before applying any controlling measures for a problem, it should always be kept in mind that it should not have negative effects on other food systems.
Answer No 5 is false because as the females Anopheles are harmful, they should be killed. The male Anopheles are not harmful hence, they should not be killed.
C A T A C T G A A
Hope this helps
What the other person said!
They r able to dig down by eating soil, then eliminating them through the anus
their digestive system is able to break down decomposing plants, that is a common source of organic materials in the soil
