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1 year ago

Can someone please help me with this!!

Mathematics

1 answer:

zimovet [89]1 year ago

6 0

Answer: -7

Step-by-step explanation:

$f(-8)=-5\\\\g(4)=3\\\\\therefore -1 \cdot f(-8) -4\cdot g(4)=-1(-5)-4(3)=5-12=\boxed{-7}$

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Step-by-step explanation:

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2 years ago

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How do you do 4(x-3) you have to use distributive property to remove the parentheses..

Oksana_A [137]

Answer:

4x -12

Step-by-step explanation:

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2 years ago

Consider the function and its inverse.

Ber [7]

Answer:

The domain of $f(x)$ is restricted to $x\leq 0$ , and the domain of $f^{-1}(x)$ is restricted to $x\geq 4$ .

Step-by-step explanation:

From Function Theory we know that domain of a function is the set of values such that an image exist. Let $f(x) = x^{2}+4$ and $f^{-1}(x) = \sqrt{x-4}$ the function and its inverse, respectively.

At first glance we notice that function is a second order polynomial and every polinomial is a continuous function and therefore, there exists an image for every element of domain.

But domain of its inverse is restricted to every value of x so that $x-4 \geq 0$ , which means that $x\geq 4$ .

Finally, we concluded that following answer offers the best approximation to our result:

The domain of $f(x)$ is restricted to $x\leq 0$ , and the domain of $f^{-1}(x)$ is restricted to $x\geq 4$ .

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2 years ago