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Anton [14]
2 years ago
13

Can someone please help me with this!!

Mathematics
1 answer:
zimovet [89]2 years ago
6 0

Answer: -7

Step-by-step explanation:

f(-8)=-5\\\\g(4)=3\\\\\therefore -1 \cdot f(-8) -4\cdot g(4)=-1(-5)-4(3)=5-12=\boxed{-7}

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Greater than or less than the base?
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I think grater then?

Step-by-step explanation:

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3 years ago
PLEASE I NEED THESE ANSWERS, ANY WOULD HELP :,(
Xelga [282]
The answer to the second one is 243/2 but I'm not 100% positive
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Solve for y 2x-5y=10
scZoUnD [109]

Answer:

y = 2/5x - 2

Step-by-step explanation:

Step 1: Write equation

2x - 5y = 10

Step 2: Solve for <em>y</em>

  1. Subtract 2x on both sides: -5y = 10 - 2x
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4 years ago
Read 2 more answers
Look at picture. Does anybody know the answer I’m lost?
masha68 [24]

Let x,y be the dimensions of the rectangle. We know the equations for both area and perimeter:

A=xy=36

P=2(x+y)=36 \iff x+y=18

So, we have  the following system:

\begin{cases}xy=36\\x+y=18\end{cases}

From the second equation, we can deduce

y=18-x

Plug this in the first equation to get

xy=x(18-x)=-x^2+18=36

Refactor as

x^2-18x+36=0

And solve with the usual quadratic formula to get

x=9\pm3\sqrt{5}

Both solutions are feasible, because they're both positive.

If we chose the positive solution, we have

x=9+3\sqrt{5} \implies y=18-x=18-9-3\sqrt{5}=9-3\sqrt{5}

If we choose the negative solution, we have

x=9-3\sqrt{5} \implies y=18-x=18-9+3\sqrt{5}=9+3\sqrt{5}

So, we're just swapping the role of x and y. The two dimensions of the rectangle are 9+3\sqrt{5} and 9-3\sqrt{5}

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