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kifflom [539]
2 years ago
11

On a snowy day 85% of the students of Wilson high school were present. If 572 of the students were present, how many students we

re enrolled at the school?
Mathematics
2 answers:
creativ13 [48]2 years ago
8 0

Answer:

673 students

Step-by-step explanation:

Divide the number of students who applied and the decimal of the percentage they represent.

85% = 85/100 = 0.85

572/.85 = 673

Hope this helps

r-ruslan [8.4K]2 years ago
7 0

Answer:

673

Step-by-step explanation:

okay so uh this is my way and the answer works so like yea teachers dont show like this but ii figured this works

okay so

85/100 = 572/?

so if you divide 85 by 85 its gonna equal 1 and 1 times 100 is gonna be 100

useing the same concept, it should be the same with 572 , but instead of divideing by 572, divide by 85.

basically 572/85

okay now thats gonna give you 6.72941176471 thats vasically 1% of the population.

so multiply 6.72941176471 * 100

so now you have

672.941176471 and you can round this to 673 kids.

and you know its right since 85% of 673 is 572.05 and you can sound to 572

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Katen [24]

Answer: y=-0.5x+4.5

Step-by-step explanation: y=mx+b, m is the slope = -1/2 or -0.5, and b is the y-int, which is 4.5

3 0
2 years ago
P(X< ) 1-P(X> ) A softball pitcher has a 0.626 probability of throwing a strike for each curve ball pitch. If the softball
Mashutka [201]

Answer:

19.49% probability that no more than 16 of them are strikes

Step-by-step explanation:

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 30, p = 0.626

So

\mu = E(X) = np = 30*0.626 = 18.78

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{30*0.626*0.374} = 2.65

What is the probability that no more than 16 of them are strikes?

Using continuity correction, this is P(X \leq 16 + 0.5) = P(X \leq 16.5), which is the pvalue of Z when X = 16.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.5 - 18.78}{2.65}

Z = -0.86

Z = -0.86 has a pvalue of 0.1949

19.49% probability that no more than 16 of them are strikes

7 0
3 years ago
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riadik2000 [5.3K]

Answer:

a^2b^7

Step-by-step explanation:

dividing exponents is basically subtracting the top exponent by the bottom. So, 3 - 1 = 2, thus giving you a^2, and 9 - 2 = 7, giving you b^7

4 0
3 years ago
Read 2 more answers
How to solve this equation
mariarad [96]
\bf \sqrt{5x+19}-4=3x-15
\\\\
\sqrt{5x+19}=3x-15+4\\\\ \sqrt{5x+19}=3x-11\leftarrow \textit{square both sides}
\\\\
(\sqrt{5x+19})^2=(3x-11)^2
\\\\
5x+19=(3x-11)^2\qquad 
\begin{cases}
(3x-11)^2\to (3x-11)(3x-11)\\
 --------------\\
\textit{or use FOIL to expand it}
\end{cases}

then solve for "x"
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3 years ago
A manufacturer samples 100 wires for quality testing. 4 wires were found defective. if 750 were produced in 1 hour how many shou
Andreyy89
30 wires would be defective

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3 years ago
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