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kifflom [539]
2 years ago
11

On a snowy day 85% of the students of Wilson high school were present. If 572 of the students were present, how many students we

re enrolled at the school?
Mathematics
2 answers:
creativ13 [48]2 years ago
8 0

Answer:

673 students

Step-by-step explanation:

Divide the number of students who applied and the decimal of the percentage they represent.

85% = 85/100 = 0.85

572/.85 = 673

Hope this helps

r-ruslan [8.4K]2 years ago
7 0

Answer:

673

Step-by-step explanation:

okay so uh this is my way and the answer works so like yea teachers dont show like this but ii figured this works

okay so

85/100 = 572/?

so if you divide 85 by 85 its gonna equal 1 and 1 times 100 is gonna be 100

useing the same concept, it should be the same with 572 , but instead of divideing by 572, divide by 85.

basically 572/85

okay now thats gonna give you 6.72941176471 thats vasically 1% of the population.

so multiply 6.72941176471 * 100

so now you have

672.941176471 and you can round this to 673 kids.

and you know its right since 85% of 673 is 572.05 and you can sound to 572

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Ratling [72]

This question is Incomplete because it lacks the diagram of the box plot. Please find attached the diagram of the box plot

Answer:

B) 102 ounces

Step-by-step explanation:

Looking at the attached diagram, we can see the box plot it divided into different segment

The median weight of the babies = 110 ounces

The maximum weight of the babies is between = 140 and 130, approximately let's say 135 ounces

The minimum weight is 80 ounces

Then the box in the middle is divided into 3

It has the First Quartile

Median

And third Quartile

Since we have 160 infants born in the local hospital, about 40 of the birthweights we fall into

= 40/160 = 1/4

1/4 represents the first Quartile

Looking at the box plot, 40 of the birthweights were below 102 ounces.

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3 years ago
Pls Help Find the area of the trapezoids
MariettaO [177]

Answer:

The area of the trapezoid is 10.5

6 0
3 years ago
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How many cups are in 4 liters? (1 liter = 1.06 quarts and 1 quart=4 cups)
Lynna [10]

Answer:

16.907

Step-by-step explanation:

7 0
3 years ago
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According to records, the amount of precipitation in a certain city on a November day has a mean of 0.10 inches; with a standard
Alecsey [184]

Answer:

Probability that the mean daily precipitation will be 0.09 inches or less for a random sample of 40 November days is 0.103.

Step-by-step explanation:

We are given that according to records, the amount of precipitation in a certain city on a November day has a mean of 0.10 inches; with a standard deviation of 0.05 inches.

A random sample of 40 November days is taken(taken over many years).

<u><em>Let </em></u>\bar X<u><em> = sample mean daily precipitation</em></u>

The z score probability distribution for sample mean is given by;

                                 Z = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \mu = population mean = 0.10 inches

           \sigma = population standard deviation = 0.05 inches

           n = sample of days = 40

Now, the probability that the mean daily precipitation will be 0.09 inches or less is given by = P( \bar X \leq 0.09 inches)

 P(\bar X \leq 0.09 inches) = P( \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } } \leq \frac{0.09-0.10}{\frac{0.05}{\sqrt{40} } } ) = P(Z \leq -1.265) = 1 - P(Z < 1.265)

                                                                    = 1 - 0.8971 = <u>0.1029</u>

<em>The above probability is calculated by looking at the value of x = 1.265 from the z table which will lie between x = 1.26 and x = 1.27 which has an area of 0.89617 and 0.89796 respectively.</em>

Hence, the probability that the mean daily precipitation will be 0.09 inches or less for a random sample of 40 November days is 0.103.

8 0
3 years ago
I need some help with this math problem help me out please... ​
goblinko [34]

Answer:

29

Step-by-step explanation:

(7-5)^2 is 4 and (20-19)^2 is 1

4+1=5

3*5=15

15+14=29

6 0
3 years ago
Read 2 more answers
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