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siniylev [52]
4 years ago
12

Given right triangle DEF, what is the value of tan(F)?

Mathematics
2 answers:
Nataly [62]4 years ago
5 0

Answer: \frac{40}{9}

Step-by-step explanation:

We know that for any angle x in a triangle ,

\tan x=\frac{\text{side opposite to x}}{\text{side adjacent to x}}

Now, for the given triangle DEF, the value of tan(F) is given by :-

\tan F=\frac{\text{side opposite to F}}{\text{side adjacent to F}}\\\\\Rightarrow\ \tan F=\frac{40}{9}

Hence, the value of tan(F) = =\frac{40}{9}

IgorC [24]4 years ago
4 0

we know that

In the right triangle DEF

the tangent of the angle F is equal to

tan(F)=\frac{opposite\ side\ angle\ F}{adjacent\ side\ angle\ F}=\frac{DE}{EF}

substitute the values

tan(F)=\frac{40}{9}

therefore

<u>the answer is the option</u>

\frac{40}{9}

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