Answer:
Function 2 has a greater initial valueStep-by-step explanation:An initial value of a function, aka y-intercept, is obtained by using x=0 and evaluating the function at that point. Evaluating the two functions given:Function1: Function2 has value 3 for x=0So, Function 2 has a greater initial valueFunction 2 has a greater initial valueStep-by-step explanation:An initial value of a function, aka y-intercept, is obtained by using x=0 and evaluating the function at that point. Evaluating the two functions given:Function1: Function2 has value 3 for x=0So, Function 2 has a greater initial value
Step-by-step explanation:
Answer:
50%: day 13
100%: day 26
Step-by-step explanation:
We are given two days and the amount of the moon that is illuminated. The two days are points on a straight line.
(1, 0.02), (2, 0.06)
y = mx + b
m = (0.06 - 0.02)/(2 - 1) = 0.04
y = 0.04x + b
0.02 = 0.04(1) + b
b = -0.02
y = 0.04x - 0.02
We want y = 50% = 0.5
0.04x - 0.02 = 0.5
0.04x = 0.52
x = 13
y = 100% = 1
0.04x - 0.02 = 1
0.04x = 1.02
x = 25.5
Answer:
end of third year = 1,200*(1.02)^3 = 1,273.45 plus
end of second year = 1,200*(1.02)^2 = 1,248.48 plus
end of first year = 1,200*(1.02) = 1,224.00
Total = 3,745.9
Step-by-step explanation:
The inverse of this would be
