Sounds as tho' you have an isosceles triangle (a triangle with 2 equal sides). If this triangle is also a right triangle (with one 90-degree angle), then the side lengths MUST satisfy the Pythagorean Theorem.

Let's see whether they do.

8^2 + 8^2 = 11^2 ???
64 + 64 = 121? NO. This is not a right triangle.

If you really do have 2 sides that are both of length 8, and you really do have a right triangle, then:

8^2 + 8^2 = d^2, where d=hypotenuse. Then 64+64 = d^2, and

d = sqrt(128) = sqrt(8*16) = 4sqrt(8) = 4*2*sqrt(2) = 8sqrt(2) = 11.3.

11 is close to 11.3, but still, this triangle cannot really have 2 sides of length 8 and one side of length 11.

7 0

3 years ago

A set of equations is given below:

artcher [175]

Answer:

comparing both equation we get,

2X+1=X+9

or, X=8

Y=X+9

or, Y=17

therefore the required solution is (8,17)

7 0

3 years ago