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1 year ago

............help ?????????????

Mathematics

2 answers:

andriy [413]1 year ago

5 0

<u>Answer:</u>

x = 75°

<u>Step-by-step explanation:</u>

∠ p = 40° [alternate interior angles]

∠ q = 35° [alternate interior angles]

x = ∠ p + ∠ q

x = 40° + 35°

x = 75°

Bumek [7]1 year ago

4 0

Step-by-step explanation:

<h3>Solution.</h3><h3>x+40°+35°=180°(straight line)</h3><h3>x+75°=180°</h3><h3>x=180°-75°</h3><h2>x<u>=105</u></h2>

<u>hope </u><u>it </u><u>helps!</u><u>!</u>

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Answer:

Step-by-step explanation:

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2 years ago

What’s the answer to this?<br> I have no idea how to do it

Nimfa-mama [501]

Answer:

Step-by-step explanation:

f(x) = y

To find f(2), it means to find the value of y when x = 2.

From the graph, when x = 2, the corresponding y-coordinate = 0.

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2 years ago

Help me plz, I need the solutions of all of them. Thank you very much

arsen [322]

Answer:

Question 6: 1/4

Question 7: 3/20

Question 8: 13/20

Question 9: They are not independent.

Explanation:

<u />

<u>1. Build a two-way frequency table filling only the initial information:</u>

Take AMS1303 No take AMS1303 Total

Take FIN1001 25 40

No take FIN1001

Total 50 100

<u />

<u>2. Complete the table calculating the missing values by differences:</u>

Take AMS1303 only: 50 - 25 = 25
No take AMS1303 and take FIN1001: 40 - 25 = 15
No take AMS1303: 100 - 50 = 50
No take FIN1001: 100 - 40 = 60
No take AMS and no take FIN: 60 - 25 = 35

Take AMS1303 No take AMS1303 Total

Take FIN1001 25 15 40 (F)

No take FIN1001 25 35 60

Total 50 50 100 (S)

(M)

<u />

<u>3. Question 6: Probability that the chosen student takes only AMS1303</u>

P(M) - P(M∩F) = 50/100 - 25/100 = 25/100 = 1/4

<u>4. Question 7: Probability that the chosen student takes only FIN1001</u>

P(F) - P(M∩F) = 40/100 - 25/100 = 15/100 = 3/20

<u>5. Question 8: Probability that the chosen student takes AMS1303 or FIN1001</u>

P(MUF) = P(M) + P(F) - P(M∩F) = 50/100 + 40/100 - 25/100 = 65/100 = 13/20

<u />

<u>6. Question 9: Is the event of selecting a student taking AMS1303 independent of the event of selecting a student taking FIN1001?</u>

We will use contidional probability. Two events are independent only if the probability of one event is equal to the probability is the same as the probability of the event given that the other event occurs.

Is P(M|F) = P(M) ?

P(M|F) = P(M∩F) / P(F) = (25/100) / (40/100) = 25/40 = 5/8

But P(M) = 50/100 = 1/2

Then, P(M|F) ≠ P(M) , therefore they are not independent

Also, you might determine:

Is P(F|M) = P(F)?

P(F|M) = P(M∩F) / P(M) = (25/100) / (50/100) = 25/50 = 1/2

P(F) = 40/100 = 2/5

Again, of course, P(F|M) ≠ P(F), meaning that they are not independent.

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2 years ago

How many triangles does a=6 b=10 A=33° create?

GaryK [48]

Answer:

2 triangles are possible.

Step-by-step explanation:

Given

a=6

b=10

$\angle$ A=33°

To find:

Number of triangles possible ?

Solution:

First of all, let us use the <em>sine rule</em>:

As per Sine Rule:

$\dfrac{a}{sinA}=\dfrac{b}{sinB}$

And let us find the angle B.

$\dfrac{6}{sin33}=\dfrac{10}{sinB}\\sinB = \dfrac{10}{6}\times sin33\\B =sin^{-1}(1.67 \times 0.545)\\B =sin^{-1}(0.9095) =65.44^\circ$

This value is in the 1st quadrant i.e. acute angle.

One more value for B is possible in the 2nd quadrant i.e. obtuse angle which is: 180 - 65.44 = $114.56^\circ$

For the value of $\angle B = 65.44^\circ$ , let us find $\angle C$ :

$\angle A+\angle B+\angle C = 180^\circ\\\Rightarrow 33+65.44+\angle C = 180\\\Rightarrow \angle C = 180-98.44 = 81.56^\circ$

Let us find side c using sine rule again:

$\dfrac{6}{sin33}=\dfrac{c}{sin81.56^\circ}\\\Rightarrow c = 11.02 \times sin81.56^\circ = 10.89$

So, one possible triangle is:

a = 6, b = 10, c = 10.89

$\angle$ A=33°, $\angle$ A=65.44°, $\angle$ C=81.56°

For the value of $\angle B =$ $114.56^\circ$ , let us find $\angle C$ :

$\angle A+\angle B+\angle C = 180^\circ\\\Rightarrow 33+114.56+\angle C = 180\\\Rightarrow \angle C = 180-147.56 = 32.44^\circ$

Let us find side c using sine rule again:

$\dfrac{6}{sin33}=\dfrac{c}{sin32.44^\circ}\\\Rightarrow c = 11.02 \times sin32.44^\circ = 5.91$

So, second possible triangle is:

a = 6, b = 10, c = 5.91

$\angle$ A=33°, $\angle$ A=114.56°, $\angle$ C=32.44°

So, answer is : 2 triangles are possible.

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2 years ago

Kim used 1 3 pounds of chicken to make 1 2 gallons of soup. If Kim's recipe is for 1 gallon of soup, how many pounds of chicken

slavikrds [6]

Answer:

Step-by-step explanation:

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2 years ago

Read 2 more answers

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