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Zielflug [23.3K]
1 year ago
15

............help ?????????????​

Mathematics
2 answers:
andriy [413]1 year ago
5 0

<u>Answer:</u>

x = 75°

<u>Step-by-step explanation:</u>

∠ p = 40°     [alternate interior angles]

∠ q = 35°    [alternate interior angles]

x = ∠ p + ∠ q

x = 40° + 35°

x = 75°  

Bumek [7]1 year ago
4 0

Step-by-step explanation:

<h3>Solution.</h3><h3>x+40°+35°=180°(straight line)</h3><h3>x+75°=180°</h3><h3>x=180°-75°</h3><h2>x<u>=105</u></h2>

<u>hope </u><u>it </u><u>helps!</u><u>!</u>

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Answer:

First =  Poppy seed  = 3x10^-4 grams  = 0.0003 grams

Second  =  sesame seeds  =  3.64x10^-6 grams  = 0.00364 grams

third  = 250 pumpkin seeds 21 grams  = one seed 0.084 grams

Step-by-step explanation:

3.64x10^-6 kilograms *1000gr/Kilograms =  0.00364 grams

21/250 = 0.0084 grams one seeds

3 0
3 years ago
What is 6 times 5 3/4
valentina_108 [34]
The answer to this would be 34.5
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The circumference of a circle is 24pi ft. What is the area, in square feet?
dexar [7]

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Step-by-step explanation:

we need the radisu

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8 0
3 years ago
Andy and his friend Sam were walking along the road together. Andy has a big bag of marbles. Unfortunately the bottom of the bag
nataly862011 [7]
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There are three different hoses used to fill a pool: hose x, hose y, and hose z. Hose x can fill the pool in a days, hose y in b
WARRIOR [948]

Answer:

C) I and III only

Step-by-step explanation:

Let full pool is denoted by O

Days Hose x takes to fill pool O = a

Pool filled in one day x = O/a

Days Hose y takes to fill pool O = b

Pool filled in one day y = O/b

Days Hose z takes to fill pool O = c

Pool filled in one day z = O/c

It is given that

                         a>b>c

a>b>c>d\\\implies x

Days if if x+y+z fill the pool together = d

1 day if x+y+z fill the pool together =O(\frac{1}{a}+\frac{1}{b}+\frac{1}{c})=\frac{O}{d}---(1)

I) d < c

d are days when hose x, y, z are used together where as c are days when only z is used so number of days when three hoses are used together must be less than c when only z hose is used. So d < c

III) \frac{c}{3}

Using (1)

\frac{bc+ac+ab}{abc}=\frac{1}{d}\\\\d=\frac{abc}{ab+bc+ca}\\\\As\quad(a>b>c)\\(ab+bc+ca)\frac{abc}{3ab}\\\\d>\frac{c}{3}

Similarly

\frac{bc+ac+ab}{abc}=\frac{1}{d}\\\\d=\frac{abc}{ab+bc+ca}\\\\As\quad a>b>c\\(ab+bc+ca)>3bc\\\\d=\frac{abc}{ab+bc+ca}

So,

\frac{c}{3}

3 0
3 years ago
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