Answer:
0.477 is the probability that the average score of the 36 golfers was between 70 and 71.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 70
Standard Deviation, σ = 3
Sample size, n = 36
Let the average score of all pro golfers follow a normal distribution.
Formula:
P(score of the 36 golfers was between 70 and 71)
![\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}](https://tex.z-dn.net/?f=%5Ctext%7BStandard%20error%20of%20sampling%7D%20%3D%20%5Cdisplaystyle%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%20%3D%20%5Cfrac%7B3%7D%7B%5Csqrt%7B36%7D%7D%20%3D%20%5Cfrac%7B1%7D%7B2%7D)
![P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%](https://tex.z-dn.net/?f=P%2870%20%5Cleq%20x%20%5Cleq%2071%29%20%3D%20P%28%5Cdisplaystyle%5Cfrac%7B70%20-%2070%7D%7B%5Cfrac%7B3%7D%7B%5Csqrt%7B36%7D%7D%7D%20%5Cleq%20z%20%5Cleq%20%5Cdisplaystyle%5Cfrac%7B71-70%7D%7B%5Cfrac%7B3%7D%7B%5Csqrt%7B36%7D%7D%7D%29%20%3D%20P%280%20%5Cleq%20z%20%5Cleq%202%29%5C%5C%5C%5C%3D%20P%28z%20%5Cleq%202%29%20-%20P%28z%20%5Cleq%200%29%5C%5C%3D%200.977%20-%200.500%20%3D%200.477%3D%2047.7%5C%25)
![P(70 \leq x \leq 71) = 47.7\%](https://tex.z-dn.net/?f=P%2870%20%5Cleq%20x%20%5Cleq%2071%29%20%3D%2047.7%5C%25)
0.477 is the probability that the average score of the 36 golfers was between 70 and 71.
Answer: Cool!ididnt even no that!
Step-by-step explanation:
4-1/2x=10
-1/2x=6
3
so your answer would be B
hope that helps
Answer:
16
Step-by-step explanation:
The square numbers are
1² = 1
2² = 4
3² = 9
4² = 16 ← this is the closest perfect square
5² = 25 (not applicable, over 22)
Answer: yes it is a right angle triangle
Step-by-step explanation:
a^2 + b^2 = c^2
8^2+ 5^2 = ?
64 + 25 = square root of 89
square root of 89 = 9.4
when we round 9.4 it is 9
so
22- (8+5) =
22 - 13 = 9
so our answer is correct